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PropositionStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
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Kasner vacuum constraints

Statement

Let ai(t)=Ai(t/t0)pi on a nonempty open interval I⊆(0,∞), where Ai>0 are lengths in metres, t0>0 is a time in seconds, and pi∈R are dimensionless exponents. These pi are called Kasner exponents for this power-law branch; define their sums P:=∑i=13pi and Q:=∑i=13pi2. For a nonstatic datum, meaning that not all pi vanish, the geometric vacuum equation Ric⁡=0 in the C2 curvature definition of this page holds exactly when P=Q=1. If all pi=0, then the full curvature tensor vanishes, so the metric is flat in the curvature sense. These are exact statements about the specified finite-dimensional metrics; no singularity or generic cosmological conclusion follows.

Facts & Assumptions

Given: A diagonal Bianchi I datum, the power-law scale factors in the Statement, and the mathematical vacuum condition Ric⁡=0 where invoked. The inherited foundational context assumes ACω only.

[A1]

The Bianchi I product and quotient construction carries ACω and no stronger choice principle (Diagonal Bianchi I model).

[F1]

The scale factors are positive C2 lengths on I⊆(0,∞), and the definitions of Hi, H and V are those of the diagonal Bianchi I datum (Diagonal Bianchi I model).

[F2]

The local Ricci components are Ric⁡00=−∑i(H˙i+Hi2) and Ric⁡ii=ai2(H˙i+HiHΣ)/c2, with zero off-diagonal components; the only potentially nonzero curvature components are the two displayed families (Curvature components of the diagonal Bianchi I metric).

Proof

technique · direct substitution into the local curvature components
1.1givenA1F1F2algebra

Work in the inherited ACω context [A1]; the calculation itself uses only finite sums and differentiation. Put P=∑ipi and Q=∑ipi2. The power laws give Hi=pi/t, H˙i=−pi/t2, and HΣ=P/t, so [F2] yields Ric⁡00=(P−Q)/t2 and Ric⁡ii=ai2pi(P−1)/(c2t2).

2.1step 1.1algebra

Suppose not all pi vanish and Ric⁡=0. Choose an index k with pk≠0. Since ak,c,t are positive, the equation Ric⁡kk=0 from step 1.1 implies P=1. The equation Ric⁡00=0 then implies Q=P=1.

2.2step 1.1F2algebra

Conversely, if P=Q=1, step 1.1 makes every diagonal Ricci component zero, and [F2] makes every off-diagonal component zero; hence Ric⁡=0.

3.1givenF1F2algebra∎

If p1=p2=p3=0, then every Hi and H˙i is zero. Both curvature-component families in [F2] therefore vanish, and every other component is zero by that lemma, so the full curvature tensor vanishes.

Depends on

Dependency tree · 2 levels

Sources