Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Scalar curvature of a conformally Euclidean three-metric

Physical scope

A local differential-geometric identity for a Riemannian metric; it asserts no Einstein constraint or physical model.

Statement

Let E⊂R3 be a nonempty open set with Cartesian coordinates x1,x2,x3, standard Euclidean metric δ=δij dxidxj with δij=1 for i=j and 0 otherwise, inverse components δij, and Laplacian Δδ=∑i=13∂i2. Let u∈C∞(E,(0,∞)) and set h=u4δ. Form the product Lorentzian manifold M^=Rτ×E with metric g=−dτ2+h and future orientation ∂τ; its slice Σ={0}×E is a smooth spacelike hypersurface with induced metric h. Use the induced connection D and curvature convention supplied for this slice by the earlier normal-decomposition theorem. In Cartesian coordinates define Rℓbcd by R(∂c,∂d)∂b=Rℓbcd∂ℓ, Ric⁡ijh:=Rkikj, and Sh:=hijRic⁡ijh. For f=2log⁡u, write ∣df∣δ2:=δij(∂if)(∂jf). Then Sh=−8u−5Δδu.

This statement concerns a smooth positive conformal metric and its induced scalar curvature. The product construction only fixes the geometric convention; no Einstein equation, energy condition, or completeness hypothesis is imposed.

Facts & Assumptions

Given: The open Euclidean coordinate domain E, its metric δ, the positive smooth function u, and the metric h=u4δ in the Statement.

[F1]

For an induced Riemannian metric h on a smooth spacelike hypersurface, D is its Levi-Civita connection, Rh has the ambient curvature operator convention, and Sh is its scalar curvature (Gauss-Codazzi decomposition in Gaussian normal coordinates and the constraint equations in terms of the induced metric and second fundamental form, proof step 1.1 and Statement clause (c)).

[A1]

u is smooth and strictly positive, so f:=2log⁡u is smooth and h=e2fδ is a smooth Riemannian metric.

Proof

Given: [F1], [A1], and the Cartesian coordinates in the Statement.

1.1F1A1algebra

Write Γkij for the Christoffel coefficients of D in the coordinate frame. Torsion-freedom gives Γkij=Γkji, and metric compatibility gives ∂ihjk=hakΓaij+hjaΓaik. Add this identity to the one with i,j interchanged and subtract the one with i,k interchanged; using symmetry of h and Γ yields 2hkaΓaij=∂ihjk+∂jhik−∂khij. Multiplying by hℓk/2 gives the coordinate Levi-Civita formula Γℓij=12hℓk(∂ihjk+∂jhik−∂khij).

2.1step 1.1A1algebra

Since hij=e2fδij and hij=e−2fδij, substitution into step 1.1 gives Γkij=δikfj+δjkfi−δijfk, where fi=∂if and fk=δkℓfℓ.

3.1F1step 2.1algebra

In a coordinate frame the definition R(X,Y)Z=DXDYZ−DYDXZ−D[X,Y]Z gives Rℓbcd=∂cΓℓdb−∂dΓℓcb+ΓℓceΓedb−ΓℓdeΓecb; contraction in the first and third slots gives (Rich)ij=∂kΓkij−∂jΓkki+ΓkkℓΓℓij−ΓkjℓΓℓki. Substituting step 2.1 and applying the product rule gives ∂kΓkij=2fij−δijΔδf, ∂jΓkki=3fij, ΓkkℓΓℓij=6fifj−3δij∣df∣δ2, and ΓkjℓΓℓki=5fifj−2δij∣df∣δ2. Therefore (Rich)ij=−fij−δijΔδf+fifj−δij∣df∣δ2.

4.1F1A1step 3.1algebra∎

Contract the Ricci tensor in step 3.1 with hij=e−2fδij to obtain Sh=e−2f(−4Δδf−2∣df∣δ2). For f=2log⁡u, the chain rule gives Δδf=2u−1Δδu−2u−2∣du∣δ2 and ∣df∣δ2=4u−2∣du∣δ2. The two ∣du∣δ2 contributions cancel, and e−2f=u−4, so Sh=−8u−5Δδu.

Remarks

The identity is proved here from the library's curvature sign convention. It is used only for explicit smooth conformal metrics; no scalar-curvature sign condition or completeness assertion is assumed.

Depends on

Dependency tree · 2 levels

Sources