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Asymptotic ends and ADM surface integrals

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

A specified asymptotically Euclidean ADM end

Physical scope

A fixed-chart geometric definition of an asymptotic energy limit; no Einstein constraint, positivity, coordinate-invariance, or empirical claim is included.

Definition

For the geometric initial-data convention, let (M,g) be a smooth time-oriented Lorentzian four-manifold and let ι:Σ↪M be a smooth embedded three-manifold whose induced metric h:=ι∗g is positive definite. Its future unit normal n satisfies g(n,n)=−1 and g(n,X)=0 for X∈TΣ. The second fundamental form is K(X,Y):=g(∇Xn,Y), with ∇ the Levi-Civita connection of g and the curvature sign convention stated in the Definition references section. The end data below are specified as a Riemannian metric and a symmetric tensor of these types; no embedding or Einstein constraint equation is required.

Let E={x∈R3:r>R0}, where R0>0 is a length, x=(x1,x2,x3) are Cartesian coordinates measured in metres, and r:=(x1)2+(x2)2+(x3)2. Write δ:=δij dxidxj for the standard Euclidean metric, where δij=1 if i=j and 0 otherwise; repeated spatial indices are summed over 1,2,3. A fixed-chart asymptotically Euclidean end consists of this exterior domain, a C2 symmetric positive-definite covariant 2-tensor h=hij dxidxj, and a C1 symmetric covariant 2-tensor K=Kij dxidxj such that hij(x)=δij+aijr+ρij(x),Kij(x)=O1(r−2), where aij=aji is a constant real matrix, ϵ>0, and ρ=O2(r−1−ϵ). For any tensor components Tij, the notation T=Ok(r−q) means that for every multi-index α=(α1,α2,α3) with ∣α∣:=α1+α2+α3≤k there are constants Cα,Rα such that ∣∂αTij(x)∣≤Cαr−q−∣α∣ for r≥Rα, uniformly in angle. Thus the definition requires two Cartesian derivatives of the metric remainder and one of K. The coordinates and r have units of metres; δij and hij are dimensionless, aij has units of metres, and K has inverse-length units in a spatial orthonormal frame.

For R>R0, the coordinate sphere SR:={x:r=R} is a smooth embedded surface in E. Let ȷR:SR↪E be its inclusion and γR:=ȷR∗δ its induced Riemannian metric. The Euclidean area measure dS is the Riemannian area measure of γR: for any smooth rank-two local parametrization X:U⊆R2→SR with coordinates (y1,y2), its coordinate density is dS=det⁡[δ(∂yaX,∂ybX)]a,b=12 dy1dy2.

The change-of-variables formula makes this density independent of the chosen surface coordinates; since x is measured in metres, dS has units of square metres. The sphere's outward Euclidean unit normal has components ni:=xi/R. If its limiting integral exists as R→∞—the spatial-infinity limit in this chosen chart—the fixed-chart ADM energy and its associated mass are EADM(h;x):=c416πGNlim⁡R→∞∫SR(∂jhij−∂ihjj)ni dS,MADM:=EADMc2. Here c>0 is the SI speed-of-light conversion constant with units metres per second, and GN>0 is the Newtonian gravitational conversion constant with units metres cubed per kilogram per second squared. The limit has units of metres, EADM has units of joules, and MADM has units of kilograms. The prefactor fixes the asymptotic time-translation normalization; in SI coordinates use x0=ct. No rescaling of this convention is part of the definition.

Conventions and scope

The formula depends only on h, not on K; the stated decay of K records the initial-data setting. This definition does not assert that (h,K) satisfies the Einstein constraint equations, that the limit is invariant under changes of chart, or that the energy is positive. It is a limit at spatial infinity, not a finite-radius surface value or a local gravitational energy density. Angular momentum and center of mass require additional decay and parity hypotheses and are outside this definition.

The sketch is a two-dimensional section through the Cartesian end. The shaded disk is excluded from E, its dashed boundary is r=R0, and the outer circle is a representative coordinate sphere SR with R>R0. The arrow at the outer circle points along the outward Euclidean unit normal ni=xi/R. The sketch suppresses the other angular directions and plays no role in any proof; the definitions above specify the full three-dimensional objects.

R0R>R0ni=xi=Rradialsectionthroughtheend
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Scalar curvature of a conformally Euclidean three-metric

Physical scope

A local differential-geometric identity for a Riemannian metric; it asserts no Einstein constraint or physical model.

Statement

Let E⊂R3 be a nonempty open set with Cartesian coordinates x1,x2,x3, standard Euclidean metric δ=δij dxidxj with δij=1 for i=j and 0 otherwise, inverse components δij, and Laplacian Δδ=∑i=13∂i2. Let u∈C∞(E,(0,∞)) and set h=u4δ. Form the product Lorentzian manifold M^=Rτ×E with metric g=−dτ2+h and future orientation ∂τ; its slice Σ={0}×E is a smooth spacelike hypersurface with induced metric h. Use the induced connection D and curvature convention supplied for this slice by the earlier normal-decomposition theorem. In Cartesian coordinates define Rℓbcd by R(∂c,∂d)∂b=Rℓbcd∂ℓ, Ric⁡ijh:=Rkikj, and Sh:=hijRic⁡ijh. For f=2log⁡u, write ∣df∣δ2:=δij(∂if)(∂jf). Then Sh=−8u−5Δδu.

This statement concerns a smooth positive conformal metric and its induced scalar curvature. The product construction only fixes the geometric convention; no Einstein equation, energy condition, or completeness hypothesis is imposed.

Facts & Assumptions

Given: The open Euclidean coordinate domain E, its metric δ, the positive smooth function u, and the metric h=u4δ in the Statement.

[F1]

For an induced Riemannian metric h on a smooth spacelike hypersurface, D is its Levi-Civita connection, Rh has the ambient curvature operator convention, and Sh is its scalar curvature (Gauss-Codazzi decomposition in Gaussian normal coordinates and the constraint equations in terms of the induced metric and second fundamental form, proof step 1.1 and Statement clause (c)).

[A1]

u is smooth and strictly positive, so f:=2log⁡u is smooth and h=e2fδ is a smooth Riemannian metric.

Proof

Given: [F1], [A1], and the Cartesian coordinates in the Statement.

1.1F1A1algebra

Write Γkij for the Christoffel coefficients of D in the coordinate frame. Torsion-freedom gives Γkij=Γkji, and metric compatibility gives ∂ihjk=hakΓaij+hjaΓaik. Add this identity to the one with i,j interchanged and subtract the one with i,k interchanged; using symmetry of h and Γ yields 2hkaΓaij=∂ihjk+∂jhik−∂khij. Multiplying by hℓk/2 gives the coordinate Levi-Civita formula Γℓij=12hℓk(∂ihjk+∂jhik−∂khij).

2.1step 1.1A1algebra

Since hij=e2fδij and hij=e−2fδij, substitution into step 1.1 gives Γkij=δikfj+δjkfi−δijfk, where fi=∂if and fk=δkℓfℓ.

3.1F1step 2.1algebra

In a coordinate frame the definition R(X,Y)Z=DXDYZ−DYDXZ−D[X,Y]Z gives Rℓbcd=∂cΓℓdb−∂dΓℓcb+ΓℓceΓedb−ΓℓdeΓecb; contraction in the first and third slots gives (Rich)ij=∂kΓkij−∂jΓkki+ΓkkℓΓℓij−ΓkjℓΓℓki. Substituting step 2.1 and applying the product rule gives ∂kΓkij=2fij−δijΔδf, ∂jΓkki=3fij, ΓkkℓΓℓij=6fifj−3δij∣df∣δ2, and ΓkjℓΓℓki=5fifj−2δij∣df∣δ2. Therefore (Rich)ij=−fij−δijΔδf+fifj−δij∣df∣δ2.

4.1F1A1step 3.1algebra∎

Contract the Ricci tensor in step 3.1 with hij=e−2fδij to obtain Sh=e−2f(−4Δδf−2∣df∣δ2). For f=2log⁡u, the chain rule gives Δδf=2u−1Δδu−2u−2∣du∣δ2 and ∣df∣δ2=4u−2∣du∣δ2. The two ∣du∣δ2 contributions cancel, and e−2f=u−4, so Sh=−8u−5Δδu.

Remarks

The identity is proved here from the library's curvature sign convention. It is used only for explicit smooth conformal metrics; no scalar-curvature sign condition or completeness assertion is assumed.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

ADM energy of a conformally flat end

Physical scope

A fixed-chart calculation for a conformally flat end; no constraint equation, positivity result, or empirical claim is inferred.

Statement

On a fixed-chart end E={x∈R3:r=∣x∣>R0} with the ADM convention stated below, let u∈C∞(E,(0,∞)) satisfy u=1+m/(2r)+ρ, where m∈R has units of metres and ρ=O2(r−2). Set h=u4δ and choose any C1 symmetric tensor K=O1(r−2). Then the ADM limit exists in the specified chart and EADM(h;x)=c4mGN.

Facts & Assumptions

Given: The fixed Cartesian end and ADM convention of A specified asymptotically Euclidean ADM end, a smooth positive u=1+m/(2r)+ρ with ρ=O2(r−2), and h=u4δ.

[F1]

On the fixed chart, EADM is c4/(16πGN) times the limit of ∫SR(∂jhij−∂ihjj)ni dS, where dS is induced by δ∣SR and a local parametrization X has density det⁡[δ(∂yaX,∂ybX)]a,b=12 dy1dy2; O2(r−q) controls Cartesian derivatives of order k≤2 by O(r−q−k) uniformly in angle; c and GN have the SI units stated in the definition (A specified asymptotically Euclidean ADM end).

[A1]

m is a real length parameter, u is strictly positive on E, and the remainder bounds are uniform in angle, as required by the Statement.

Proof

Given: [F1], [A1], and the conformally flat metric in the Statement.

1.1F1A1algebra

Set w:=m/(2r)+ρ. Derivatives of r−1 satisfy ∂α(r−1)=O(r−1−∣α∣) for ∣α∣≤2, since each derivative is homogeneous of degree −1−∣α∣ and bounded on the unit sphere. Together with ρ=O2(r−2), this gives w=O2(r−1); the product rule gives w2,w3,w4=O2(r−2). Also 4w=2m/r+O2(r−2), so the binomial expansion u4=(1+w)4=1+4w+6w2+4w3+w4 yields hij=δij+(2mδij)/r+O2(r−2). Since u>0, h is positive definite and C2, and the supplied symmetric K is C1 with O1(r−2) decay. Thus (h,K) satisfies the definition of a fixed-chart end with aij=2mδij and ϵ=1. Now hij=u4δij gives ∂jhij=∂i(u4) and hjj=3u4, hence ∂jhij−∂ihjj=−2∂i(u4)=−8u3∂iu. Contracting with ni=xi/R on SR replaces ∂iu by ∂ru.

2.1F1A1step 1.1algebra

The radial derivative bounds in [F1] and ρ=O2(r−2) give u∣SR=1+m/(2R)+O(R−2) and ∂ru∣SR=−m/(2R2)+O(R−3), uniformly in angle. Thus u3=1+O(R−1), so step 1.1's contracted integrand is 4m/R2+O(R−3), uniformly on SR.

3.1F1step 2.1algebra

Parameterize the complement of the poles and one meridian in SR by XR(θ,φ)=R(sin⁡θcos⁡φ,sin⁡θsin⁡φ,cos⁡θ), with coordinates y1=θ∈(0,π) and y2=φ∈(0,2π). Its coordinate tangent vectors are ∂θXR=R(cos⁡θcos⁡φ,cos⁡θsin⁡φ,−sin⁡θ) and ∂φXR=R(−sin⁡θsin⁡φ,sin⁡θcos⁡φ,0), so the induced-metric Gram matrix is [δ(∂yaXR,∂ybXR)]a,b=12=(R200R2sin⁡2θ), with determinant R4sin⁡2θ. The area-measure definition in [F1] therefore gives dS=R2sin⁡θ dθ dφ. The omitted poles and meridian have area zero, so integrating the uniform expansion in step 2.1 over this chart yields ∫SR(∂jhij−∂ihjj)ni dS=16πm+O(R−1), since ∫02π∫0πsin⁡θ dθ dφ=4π. This proves the limit exists.

4.1F1step 3.1algebra∎

Multiplying the limit in step 3.1 by c4/(16πGN) from [F1] gives EADM=c4m/GN. The dimensions are (c4/GN)×m=J, as specified in [F1].

Remarks

The proof uses the fixed chart and the exact stated falloff. It proves neither coordinate invariance for broader asymptotic classes nor a positivity theorem.

PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)Open item page →

Compact interior changes leave a fixed ADM integral unchanged

Physical scope

A fixed-chart equality of asymptotic limits under compactly supported metric changes; no field equation or positivity result is used.

Statement

Let h and h′ be two C2 Riemannian metrics on the same end E={x∈R3:r=∣x∣>R0}, with the same fixed Cartesian chart and asymptotic time normalization stated below. Suppose h=h′ outside a compact set C⊂E and both fixed-chart ADM limits exist. Then EADM(h;x)=EADM(h′;x). The symmetric tensors K associated with the two data sets may differ; each need only satisfy the decay in the definition.

Facts & Assumptions

Given: The same end chart and ADM formula for both metrics, a compact set C⊂E, equality h=h′ on E∖C, and existence of both limits.

[F1]

The ADM integrand in the fixed chart is (∂jhij−∂ihjj)ni on SR, with the same constant prefactor for both metrics; K does not enter that formula (A specified asymptotically Euclidean ADM end).

[A1]

The two limits exist, and the metrics agree on the complement of the same compact set in the same chart, as stipulated.

Proof

Given: [F1], [A1], and the two metrics in the Statement.

1.1A1algebra

If C is nonempty, continuity of r on compact C gives a finite RC=max⁡x∈Cr(x). If C is empty, set RC=R0. For every R>RC, the sphere SR is disjoint from C and lies in the open set E∖C, on which h=h′. Since the metrics agree on this open set, their first Cartesian derivatives also agree at every point of SR.

2.1F1A1step 1.1algebra∎

By [F1] and step 1.1, the two integrands coincide pointwise on every SR with R>RC, so the two surface integrals are equal for all such R. Taking the limits, which exist by [A1], gives equal limits. Multiplication by the common factor c4/(16πGN) proves the equality of ADM energies.

Remarks

This is a fixed-chart statement. It makes no claim of diffeomorphism invariance, constraint preservation, completeness, or scalar-curvature equality.

5 · Examples, experiments and counterexamples

None yet.

Sources