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Uniform area quantum and finite homology classes for closed tame holomorphic curves
Statement
Assume full AC. Let be a compact closed symplectic manifold. For a fixed smooth -tame almost-complex structure , or uniformly for in a compact smooth family of such structures, there is such that every nonconstant -holomorphic map from ANY connected compact closed Riemann surface has symplectic area at least . The constant is independent of the domain's genus and complex structure. The assertion applies to every nonconstant normalization component of a nodal stable map.
For each , only finitely many classes in can be represented by a -holomorphic closed curve, or a finite sum of such curves, of total symplectic area at most . The same finiteness is uniform in the indicated compact tame family. In particular a nodal map of area has at most nonconstant components. No boundary or inhomogeneous Floer assertion is included.
Facts & Assumptions
Given: The compact symplectic target, its fixed tame or specified compact smooth tame family, and full AC. A closed domain has no boundary; energy below uses the usual conformal Dirichlet convention .
The symplectic orientation makes a closed oriented manifold; its integral homology is finitely generated. Finite generation from cap with a finite fundamental cycle
The evaluation map is onto. Topological universal coefficient short exact sequence for cohomology
Every such real cohomology class is represented by a smooth closed two-form, with natural evaluation by integration on a smooth closed surface. The de Rham theorem
Full AC is used through [F1] and [F2]: their Poincaré-duality finite-generation and topological UCT arguments state that premise. [F3] needs only countable choice. The finite list of auxiliary forms chosen in step 1.1 adds no further choice use. The Axiom of Choice
Proof
Under [A1], by [F1], write , with finite, and choose the dual coordinate homomorphisms to . By [F2–F3], choose smooth closed forms such that . In particular these numbers are integers. This does not assume that the periods of form a discrete subgroup; those periods can be dense. There are only finitely many chosen auxiliary forms.
Tameness and compactness give constants and with Choose any fixed target metric. The same constants work over a compact tame family: the continuous positive function on its unit tangent sphere has a positive minimum, and each form expression has a finite maximum. Set . For any -holomorphic map, an oriented orthonormal domain frame gives , whence pointwise Integrating gives , without any restriction on the domain geometry. The same inequality adds over finitely many components.
Choose with for every , taking any positive if . If a closed holomorphic map had area , every integer would have absolute value below one and hence be zero. Its homology class would therefore be torsion. A real closed form evaluates to zero on a torsion cycle: if , then in . Thus its area would be zero, a contradiction. Area zero itself forces pointwise by the positive tame inequality; connectedness then makes the map constant. This proves the uniform domain-independent quantum.
If total area is at most , step 2.1 confines every free coordinate to the finite integer interval . The torsion coordinate lies in the finite set . Their product contains only finitely many integral homology classes. Every nonconstant normalization component has area at least by step 3.1, and each constant component has zero area. Summing the nonnegative component areas gives the stated component bound. These arguments also cover a disconnected target (it has finitely many components) and the case , where no nonconstant closed tame holomorphic map exists. Boundary and inhomogeneous maps lack the closed integral two-cycle used here and have not been included.