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Uniform area quantum and finite homology classes for closed tame holomorphic curves

Statement

Assume full AC. Let (X,ω) be a compact closed symplectic manifold. For a fixed smooth ω-tame almost-complex structure J, or uniformly for J in a compact smooth family of such structures, there is h>0 such that every nonconstant J-holomorphic map from ANY connected compact closed Riemann surface has symplectic area at least h. The constant is independent of the domain's genus and complex structure. The assertion applies to every nonconstant normalization component of a nodal stable map.

For each A<∞, only finitely many classes in H2(X;Z) can be represented by a J-holomorphic closed curve, or a finite sum of such curves, of total symplectic area at most A. The same finiteness is uniform in the indicated compact tame family. In particular a nodal map of area A has at most ⌊A/h⌋ nonconstant components. No boundary or inhomogeneous Floer assertion is included.

Facts & Assumptions

Given: The compact symplectic target, its fixed tame J or specified compact smooth tame family, and full AC. A closed domain has no boundary; energy below uses the usual conformal Dirichlet convention 12∫∣du∣2.

[F1]

The symplectic orientation makes X a closed oriented manifold; its integral homology is finitely generated. Finite generation from cap with a finite fundamental cycle

[F2]

The evaluation map H2(X;R)→Hom⁡(H2(X;Z),R) is onto. Topological universal coefficient short exact sequence for cohomology

[F3]

Every such real cohomology class is represented by a smooth closed two-form, with natural evaluation by integration on a smooth closed surface. The de Rham theorem

[A1]

Full AC is used through [F1] and [F2]: their Poincaré-duality finite-generation and topological UCT arguments state that premise. [F3] needs only countable choice. The finite list of auxiliary forms chosen in step 1.1 adds no further choice use. The Axiom of Choice

Proof

1.1A1F1F2F3givenconstructalgebra

Under [A1], by [F1], write H2(X;Z)=Zr⊕T, with T finite, and choose the dual coordinate homomorphisms a1,…,ar to R. By [F2–F3], choose smooth closed forms ηi such that ∫uηi=ai(u∗[C]). In particular these numbers are integers. This does not assume that the periods of ω form a discrete subgroup; those periods can be dense. There are only finitely many chosen auxiliary forms.

2.1givenstep 1.1constructalgebra

Tameness and compactness give constants c>0 and Mi<∞ with ωx(v,Jxv)≥c∣v∣2,∣ηi(v,Jxv)∣≤Mi∣v∣2. Choose any fixed target metric. The same constants work over a compact tame family: the continuous positive function on its unit tangent sphere has a positive minimum, and each form expression has a finite maximum. Set Ci=Mi/c. For any J-holomorphic map, an oriented orthonormal domain frame (e,je) gives du(je)=Jdu(e), whence pointwise ∣u∗ηi(e,je)∣≤Ciu∗ω(e,je). Integrating gives ∣ai(u∗[C])∣≤Ci∫Cu∗ω, without any restriction on the domain geometry. The same inequality adds over finitely many components.

3.1F3step 1.1step 2.1constructalgebra

Choose h>0 with Cih<1 for every i, taking any positive h if r=0. If a closed holomorphic map had area 0<A<h, every integer ai would have absolute value below one and hence be zero. Its homology class would therefore be torsion. A real closed form evaluates to zero on a torsion cycle: if mα=0, then m⟨[ω],α⟩=0 in R. Thus its area would be zero, a contradiction. Area zero itself forces du=0 pointwise by the positive tame inequality; connectedness then makes the map constant. This proves the uniform domain-independent quantum.

4.1F1step 1.1step 2.1step 3.1algebra∎

If total area is at most A, step 2.1 confines every free coordinate ai to the finite integer interval [−CiA,CiA]. The torsion coordinate lies in the finite set T. Their product contains only finitely many integral homology classes. Every nonconstant normalization component has area at least h by step 3.1, and each constant component has zero area. Summing the nonnegative component areas gives the stated component bound. These arguments also cover a disconnected target (it has finitely many components) and the case r=0, where no nonconstant closed tame holomorphic map exists. Boundary and inhomogeneous maps lack the closed integral two-cycle used here and have not been included.

Depends on

Dependency tree · 2 levels

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