Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite-mode Dirac first-order constraint reduction

Statement

Assume Countable Choice, the constants in Charged gauge data and SI-natural conventions, ℏ>0, and a finite integer N≥1. Let the real configuration space be Q=R2N with coordinates (x1,y1,…,xN,yN) and let T∗Q≅R4N have corresponding real canonical momentum coordinates (P1x,P1y,…,PNx,PNy). On real smooth functions define the canonical Poisson bracket {F,G}=∑j=1N(∂F∂xj∂G∂Pjx−∂F∂Pjx∂G∂xj+∂F∂yj∂G∂Pjy−∂F∂Pjy∂G∂yj), and extend it C-bilinearly to complex-valued smooth functions on T∗Q. Define the complex coordinate notation zj=xj+iyj,zˉj=xj−iyj,pj=Pjx−iPjy2,pˉj=Pjx+iPjy2. These definitions give {zj,pk}=δjk,{zˉj,pˉk}=δjk, with all other elementary brackets zero; the bracket is extended by bilinearity and the Leibniz rule. The first-order kinetic term iℏ2∑j(zˉjz˙j−zˉ˙jzj) gives primary constraints Cj=pj−iℏ2zˉj,Cˉj=pˉj+iℏ2zj. In the order (C1,…,CN,Cˉ1,…,CˉN) their constraint matrix and inverse are M=(0−iℏINiℏIN0),M−1=(0−iIN/ℏiIN/ℏ0). Here, “second class” means that the constraint matrix MAB={χA,χB} is invertible. Thus these constraints are second class. For a real smooth finite-mode Hamiltonian H∈C∞(Q;R), viewed as independent of the momenta, define the Wirtinger derivative ∂H∂zˉj:=12(∂H∂xj+i∂H∂yj). The Dirac bracket {F,G}D={F,G}−{F,χA}(M−1)AB{χB,G},χ=(C1,…,CN,Cˉ1,…,CˉN), satisfies {zj,zˉk}D=−iδjk/ℏ and {zj,zk}D={zˉj,zˉk}D=0. For a real smooth finite-mode Hamiltonian H(z,zˉ) the reduced equation is iℏz˙j=∂H/∂zˉj. These are ordinary commuting coordinates; they do not derive CAR by canonical quantization.

Facts & Assumptions

Given: Countable Choice, the charged normalization conventions, ℏ>0, a finite mode number N≥1, and the canonical brackets defined in the statement.

[A1]

The natural convention uses positive ℏ and a first-order covariant Dirac kinetic term. Charged gauge data and SI-natural conventions

[A2]
[F1]

The natural covariant derivative is Da=∂a−igaa and ℏ>0. Charged gauge data and SI-natural conventions

Proof

Given: [A1], [A2], ℏ>0, and the canonical brackets in the statement.

1.1A1A2F1givenalgebra

Under the explicit Countable Choice assumption [A2], write the displayed kinetic term in the underlying real coordinates: iℏ2∑j(zˉjz˙j−zˉ˙jzj)=ℏ∑j(yjx˙j−xjy˙j). Its real canonical momenta are therefore Pjx=ℏyj and Pjy=−ℏxj. By the complex momentum definitions in the Statement, pj=iℏzˉj/2 and pˉj=−iℏzj/2. Moving these velocity-independent expressions to the left gives exactly Cj=0 and Cˉj=0. The finite canonical calculation uses the positive ℏ fixed in [F1].

2.1A1F1step 1.1givenalgebra

For each j,k, bilinearity and the elementary brackets give {Cj,Ck}=0,{Cˉj,Cˉk}=0,{Cj,Cˉk}={pj,(iℏ/2)zk}+{−(iℏ/2)zˉj,pˉk}=−iℏ2δjk−iℏ2δjk=−iℏδjk. Antisymmetry gives {Cˉj,Ck}=iℏδjk, which is exactly the displayed block matrix M.

3.1F1step 2.1givenalgebra

Multiplication of the two displayed block matrices gives MM−1=M−1M=I2N; each off-diagonal product is (−iℏ)(i/ℏ)=1 or (iℏ)(−i/ℏ)=1, and the diagonal blocks are zero. Because ℏ>0, M is invertible, so these primary constraints are second class by definition.

4.1step 3.1givenalgebra

The canonical coordinate bracket {zj,zˉk} is zero. In the Dirac correction, the only nonzero factors are {zj,Cℓ}=δjℓ and {Cˉm,zˉk}=−δmk. Hence {zj,zˉk}D=0−δjℓ(M−1)Cℓ,Cˉm(−δmk)=(M−1)Cj,Cˉk=−iℏδjk. The same formula has no nonzero block for {zj,zk}D or {zˉj,zˉk}D, so both vanish.

5.1F1step 4.1givenalgebra∎

For a smooth H(z,zˉ), the only nonzero reduced coordinate bracket in {zj,H}D is with zˉj, so step 4.1 gives z˙j={zj,H}D=−iℏ−1∂H/∂zˉj. Multiplying by iℏ proves the stated equation. The calculation remains finite-dimensional for every N and introduces no infinite-dimensional Poisson bracket or fermionic anticommutator.

Depends on

Dependency tree · 2 levels

Sources