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Finite free map kernels over a coherent structure sheaf are locally finite type
Statement
Let be a ringed space whose structure sheaf is coherent in the sense that every finite tuple of its local sections has a locally finite-type relation sheaf. For all finite integers and every -module morphism , the kernel sheaf is locally of finite type.
Statement references
Facts & Assumptions
Given: A ringed space with coherent structure sheaf and finite integers .
Coherent module sheaves on complex manifolds: coherence of means that every finite tuple of sections of has a locally finite-type relation sheaf.
Kernel sheaves are objectwise, while cokernels and images are sheafified: the kernel sheaf of a module morphism is the subsheaf whose sections are objectwise kernels.
A sequence of abelian sheaves is exact exactly when it is exact on every stalk: equality and exactness of the relevant sheaf maps can be checked on every stalk.
Proof
Induct on the target rank . If , then , generated by its standard sections (and equal to zero if ). If , the images of the standard sections are a finite tuple in , and [F1] says its relation sheaf, which is by [F2], is locally of finite type.
Assume and the result for target rank . Let , and let drop the first coordinate. By the induction hypothesis, around any fixed the sheaf has finitely many generating sections whose germs generate every stalk on one neighborhood of .
Since lies in , write with . By [F1], after shrinking the relation sheaf of is generated on by finitely many sections . For each , define . Then because .
For any and any germ , step 2.1 gives for some germs . The first coordinate of says , so lies in the relation stalk generated by the . Hence is an -linear combination of . Thus these finitely many sections generate every kernel stalk on ; [F2] and [F3] identify the resulting subsheaf with , proving local finite type.
Proof sources
Remarks
The target-rank induction is the sheaf version of reducing a map into to its projection into and one scalar relation map. The proof above uses stalks only to verify the generated kernel; it does not use a diagram as a proof.
The projection used in the induction is recorded by the commutative diagram
Here the diagonal map is the target-rank- map whose kernel is generated by the induction hypothesis; the vertical map drops the first coordinate. The diagram fixes the map directions and adds no premise to the proof.