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Kernels, cokernels, and finite extensions of coherent module sheaves

Statement

Let (X,OX) be a ringed space and use the coherence definition on the A page. The kernel and cokernel of any morphism between coherent OX-module sheaves are coherent. In every short exact sequence 0→F′→E→F′′→0 of OX-module sheaves, if any two of F′, E, and F′′ are coherent, then the third is coherent.

Facts & Assumptions

Given: A ringed space (X,OX); an OX-module morphism f:F→G between coherent modules; and, for the extension assertion, a short exact sequence of OX-modules.

[F1]

Coherent module sheaves on complex manifolds: a coherent module is locally of finite type, and the kernel of every morphism from a finite-rank free module sheaf into it is locally of finite type.

[F2]

Kernel sheaves are objectwise, while cokernels and images are sheafified: kernels are objectwise; cokernel and image sheaves are the sheafifications of their sectionwise presheaves.

[F3]

Exact sequences of sheaves: a short exact sequence has zero kernel at the left endpoint, image equal to kernel at the middle term, and zero cokernel at the right endpoint.

[F4]

A sequence of abelian sheaves is exact exactly when it is exact on every stalk: epimorphisms and exactness in the constructions below can be checked on stalks.

Proof

1.1F1F2F3F4givenconstruct

Let F be coherent and fix x∈X. Local finite type gives, after choosing a neighborhood U of x, a finite-rank free module sheaf map π:OU⊕k→F∣U that is surjective on every stalk. By [F1], its kernel is locally of finite type; after shrinking to V⊆U, choose finitely many sections generating that kernel on V and let ρ:OV⊕m→OV⊕k be the corresponding map. The sequence OV⊕m→ρOV⊕k→πF∣V→0 is exact by [F2], [F3], and [F4]. Thus every coherent module has a local finite presentation.

2.1F1F2F4step 1.1given

Let f:F→G be a morphism of coherent modules and set K=ker⁡f. Choose locally a finite-rank free epimorphism π:O⊕k→F. The composite fπ:O⊕k→G has a locally finite-type kernel by [F1]; its image under π is exactly K on each stalk, since π is stalkwise surjective. Hence K is locally of finite type by [F4]. For every finite-rank map η:O⊕p→K, its composite with the inclusion K↪F has the same kernel; [F1] for F makes that kernel locally of finite type. Thus K is coherent.

2.2F1F2F4step 1.1construct

Let C=coker⁡f. It is locally of finite type because it is a quotient of the locally finite-type module G. To check its relation condition, fix a finite-rank map γ:O⊕p→C and a point x. Since G→C is a sheaf epimorphism, choose local lifts of the finitely many images of the standard basis near x; they define γ~:O⊕p→G lifting γ. Also choose a local finite-rank epimorphism δ:O⊕m→F. Define ϵ:O⊕(m+p)→G by ϵ(a,b)=f(δ(a))+γ~(b). By [F1], ker⁡ϵ is locally of finite type. Projection of ker⁡ϵ to the second factor has image exactly ker⁡γ on every stalk: an element of ker⁡ϵ maps to zero in C, and any stalk element b∈ker⁡γ has γ~(b)∈im⁡f, so a stalk preimage under δ completes it to an element of ker⁡ϵ. The image of a locally finite-type module is locally finite type, so ker⁡γ is locally of finite type. This holds for every γ, hence C is coherent.

3.1F2F3step 2.1step 2.2

Consider a short exact sequence 0→F′→iE→pF′′→0. If E and F′′ are coherent, then F′=ker⁡p is coherent by step 2.1. If F′ and E are coherent, then F′′=coker⁡i is coherent by step 2.2.

4.1F1F2F3F4step 3.1algebraconstruct∎

It remains to assume F′ and F′′ coherent. Local finite generators of F′ together with local lifts to E of finite generators of F′′ generate E, so E is locally of finite type. For any finite-rank map g:O⊕k→E, the kernel of pg is locally of finite type by [F1] for F′′; choose a local finite-rank epimorphism γ:O⊕m→ker⁡(pg). Exactness gives a map δ:O⊕m→F′ with iδ=gγ. By [F1] for F′, ker⁡δ is locally of finite type. On each stalk, γ maps ker⁡δ onto ker⁡g: inclusion follows from iδ=gγ, and if s∈ker⁡g, then pg(s)=0, so s=γ(t) for some t and iδ(t)=g(s)=0; injectivity of i gives δ(t)=0. Therefore ker⁡g is locally of finite type. Since this holds for every g, E is coherent.

Remarks

The extension case uses the exact sequence

0F0EF000ip

Here i is the monomorphism and p the epimorphism in the given sequence. The proof establishes finite generation of E and then its relation condition directly; the diagram only records the maps and exactness convention.

Depends on

Dependency tree · 2 levels

Sources