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Analytic negative-twist vanishings for the positive real monad

Statement

Assume full AC. Then the analytic sheaf cohomology of O(−1) vanishes in every degree on Pr(C) for 1≤r≤3. The analytic cohomology of O(−2) vanishes in every degree on Pr(C) for r=2,3. In particular, H0(P1,O(−1))=0 and Hq(P3,O(−2))=0 for q=0,1,2. This is an analytic deduction from the named scalar-cohomology supplier and does not identify algebraic and analytic cohomology by GAGA.

Facts & Assumptions

Given: Full AC and the standard holomorphic hyperplane inclusions Pr−1↪Pr for 1≤r≤3.

[A1]

Under full AC, the batch-67 scalar cohomology theorem states that for every 0≤r≤3, H0(Pr,O)=C and Hq(Pr,O)=0 for q>0. Projective Dolbeault comparison and scalar structure-sheaf cohomology

[F1]

For a hyperplane inclusion i:Pr−1↪Pr, multiplication by its defining linear form gives the exact holomorphic sequences 0→O(−1)→O→i∗OPr−1→0 and 0→O(−2)→O(−1)→i∗OPr−1(−1)→0. Exact holomorphic hyperplane sequences for negative twists

[F2]

For this closed inclusion, i∗ is exact because its stalk is the original stalk on H=Pr−1 and zero off H. The inverse-image functor i−1 is exact and left adjoint to i∗, so i∗ sends injective sheaves to injective sheaves. Also Γ(Pr,i∗G)=Γ(H,G). Applying i∗ to an injective resolution therefore gives the natural isomorphism Hq(Pr,i∗G)≅Hq(H,G) for every sheaf G on H.

[F3]

A short exact sequence of sheaves gives the natural long exact sequence in the same sheaf cohomology groups. Long exact sequence of sheaf cohomology

Proof

Given: [A1] and [F1]. All cohomology in this proof is analytic sheaf cohomology.

1.1givenA1F1F2F3algebra

Fix r∈{1,2,3}. In the first sequence of [F1], [F2] identifies the cohomology of the quotient sheaf with that of OPr−1. The map H0(Pr,O)→H0(Pr−1,O) is restriction of constants and hence is the identity C→C. Exactness therefore gives H0(Pr,O(−1))=0. The adjacent higher groups of O and OPr−1 vanish by [A1]; the long exact sequence [F3] then gives Hq(Pr,O(−1))=0 for every q>0.

2.1givenF1F2F3step 1.1algebra∎

Fix r∈{2,3}. By [F2], the second sequence of [F1] has quotient cohomology equal to that of OPr−1(−1). Both this sheaf and OPr(−1) are acyclic by step 1.1, since r−1∈{1,2}. Its long exact cohomology sequence [F3] therefore gives Hq(Pr,O(−2))=0 for every q≥0, including the stated P3 groups.

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