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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Null momenta admit unique spinor-helicity classes

Statement

For every p∈C4, det⁡κ(p)=h(p,p). Thus for every nonzero p with h(p,p)=0, κ(p) has a spinor factorization. If κ(p)aa˙=λaλ~a˙=λa′λ~a˙′, then there is a unique t∈C× such that λ′=tλ and λ~′=t−1λ~. Hence the spinor factorizations of each nonzero null momentum form exactly one equivalence class under the stated rescaling.

Facts & Assumptions

Given: p≠0, h(p,p)=0, and the coordinate-to-matrix map κ of the spinor-helicity definition.

[F1]

Complex null momenta and helicity weights: κ(p)=(p0+p3p1−ip2p1+ip2p0−p3).

[F2]

Complex null momenta and helicity weights: h(p,q)=p0q0−p1q1−p2q2−p3q3.

[F3]

Complex null momenta and helicity weights: a spinor factorization is a pair of nonzero two-spinors with Maa˙=λaλ~a˙.

[F4]

Complex null momenta and helicity weights: the explicit inverse formula for κ recovers all four coordinates from its matrix entries.

Proof

1.1givenF1F2F4algebra

Direct expansion gives det⁡κ(p)=(p0)2−(p1)2−(p2)2−(p3)2=h(p,p)=0. The explicit inverse formula in [F4] shows κ(p)≠0 because p≠0. A nonzero 2×2 matrix with determinant zero has rank one.

2.1givenF1F3step 1.1choose

Choose a nonzero column v of κ(p). Rank one means each of its two columns is a scalar multiple aa˙v; setting λ=v and λ~a˙=aa˙ gives the factorization required by [F3]. Both factors are nonzero because their product matrix is nonzero.

3.1givenstep 2.1algebra∎

Any second factorization has the same one-dimensional column space, so λ′=tλ for a unique nonzero scalar t. Equality of the outer products then gives λ~′=t−1λ~ by comparing a nonzero component of λ. This proves uniqueness of the class.

Depends on

Dependency tree · 2 levels

Sources