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Spectral permanence for unital c star subalgebras

Statement

Assume AC. If B is a unital C*-subalgebra of a unital C*-algebra A with the same identity, then σB(b)=σA(b) for every b∈B.

Facts & Assumptions

[A1]

A unital C*-algebra is a nonzero complex Banach algebra with a unit of norm one and an involution satisfying the C*-identity; a unital C*-subalgebra with the same identity is a closed unital ∗-subalgebra containing that unit (C star algebra, Unital Banach algebra).

[A2]

For every element b invertible in A the adjoint b∗ is invertible with (b∗)−1=(b−1)∗, and b∗b is positive; positivity of an element means x=y∗y for some element y (Self-adjoint positive unitary and normal elements for positivity, C star algebra for the involution rules).

[A3]

If B⊆A is a unital subalgebra with the same unit and b∈B, then σA(b)⊆σB(b), since invertibility in B implies invertibility in A (Spectrum and resolvent set in a Banach algebra).

[A4]

For a nonzero unital commutative complex C*-algebra C the Gelfand transform Γ:C→C(Δ(C)) is an isometric unital ∗-isomorphism onto C(Δ(C)), and Δ(C) is a nonempty compact Hausdorff space (Commutative Gelfand Naimark, Maximal ideal space is compact Hausdorff, Character and maximal ideal space).

[A5]

A unital self-adjoint complex function algebra that separates the points of a nonempty compact Hausdorff space is uniformly dense in all continuous complex functions (Complex Stone–Weierstrass dichotomy for separating self-adjoint algebras; the unital case is dense).

[A6]

Characters of a unital commutative complex C*-algebra satisfy χ(c∗)=χ(c)‾ (Characters on a unital commutative C star algebra preserve star).

[A7]

AC is the global hypothesis of the Gelfand-theoretic suppliers (The Axiom of Choice).

Proof

technique · direct

Given: A unital C*-algebra A, a unital C*-subalgebra B⊆A with 1B=1A, and b∈B.

1.1A3

Since invertibility in B implies invertibility in A, one has σA(b)⊆σB(b); it remains to prove the reverse inclusion, that is, that b invertible in A is invertible in B with inverse in B.

1.2A1A2algebra

If b is invertible in A, then x:=b∗b∈B is positive and invertible in A with x−1=b−1(b−1)∗; and if x positive and invertible in A has x−1∈B, then (b∗b)−1∈B and b−1=(b∗b)−1b∗∈B.

1.3A1A2A4A7algebra

It suffices to treat a self-adjoint x∈B invertible in A, because the positive element b∗b in the preceding reduction is self-adjoint. For such x, let C:=CA∗(1,x,x−1) be the closed unital star-subalgebra of A generated by x and x−1, and let D:=CA∗(1,x)⊆B. Both are commutative, because x=x∗ and (x−1)∗=x−1, and the Gelfand transform is an isometric unital star-isomorphism Γ:C→C(Δ(C)) on the nonempty compact Hausdorff character space.

2.1step 1.3A6algebra

The function x^ separates the points of Δ(C). Indeed, if characters h,h′ have h(x)=h′(x), then h(x−1)=h(x)−1=h′(x)−1=h′(x−1); they therefore agree on the unital star-algebra generated by x,x−1 and, by continuity, on its closure C, so h=h′. Moreover x^ is real-valued because x=x∗ and characters preserve the involution.

3.1step 2.1A4A5

Under Γ, the algebra D is the closed unital self-adjoint function algebra generated by x^. It separates points by step 2.1, so Stone--Weierstrass gives Γ(D)=C(Δ(C))=Γ(C). Injectivity of Γ yields D=C, hence x−1∈D⊆B.

4.1step 1.1step 1.2step 3.1∎

Therefore every b∈B invertible in A has (b∗b)−1∈B by step 3.1 and then b−1=(b∗b)−1b∗∈B by step 1.2. Thus σB(b)⊆σA(b); with step 1.1 this gives σB(b)=σA(b).

Depends on

Dependency tree · 2 levels

Sources