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Exact relative-shell canonical normalization and response

Statement

Use the relative Kepler Hamiltonian and shell Q={q∈R3:r0≤∣q∣≤R} from Regulated relative Kepler phase volume and shell law, with μ,A,r0>0 and R>16r0. For every β>0, define Zrel(β)=1h∗3∫Q∫R3e−βh(q,p) d3p d3q. Then 0<∣Q∣eβA/Rh∗3(2πμβ)3/2≤Zrel(β)≤∣Q∣eβA/r0h∗3(2πμβ)3/2<∞. All energy moments are finite, and on every compact positive β interval one integrable majorant justifies all derivatives of Zrel. Put dνrel=h∗−3d3q d3p on Q×R3 and pβ=Zrel(β)−1e−βh. For a measurable observable A:Q×R3→R with finite second moment, define ⟨A⟩β:=∫Apβ dνrel and Var⁡β(A):=∫(A−⟨A⟩β)2pβ dνrel. The normalized canonical density has ⟨h⟩β=−∂βlog⁡Zrel,d⟨h⟩βdβ=−Var⁡β(h),CK:=d⟨h⟩βdTK=kBβ2Var⁡β(h)≥0,TK=(kBβ)−1. This is the exact six-dimensional relative canonical preparation; center-of-mass degrees are absent.

Facts & Assumptions

Given: The relative phase shell and Hamiltonian, β>0, μ,A,r0>0, and R>16r0.

[F1]

The relative shell is Q={q:r0≤∣q∣≤R} and h(q,p)=∣p∣2/(2μ)−A/∣q∣, with measure d3q d3p/h∗3. (Regulated relative Kepler phase volume and shell law)

[F2]

Radial integration gives ∣Q∣=4π∫r0Rr2dr=4π3(R3−r03). (Radial integration over a bounded Euclidean shell)

[F3]

Gaussian momentum moments are finite and uniformly bounded on compact positive inverse-temperature intervals. (Finite-dimensional Gaussian normalization and moment envelope)

[F4]

Differentiation under an integral is valid when the parameter derivative has an integrable uniform majorant. (Differentiation under the integral sign)

[F5]

Tonelli factors nonnegative measurable integrals on products of sigma-finite Lebesgue spaces. (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product)

Proof

1.1F1F2F3F5algebra

On Q, −A/r0≤−A/∣q∣≤−A/R. Therefore eβA/Re−β∣p∣2/(2μ)≤e−βh(q,p)≤eβA/r0e−β∣p∣2/(2μ). The position volume is positive and finite by [F2]. Tonelli [F5] and the Gaussian formula [F3] integrate the momentum factor as (2πμ/β)3/2, proving both strict positivity and the stated finite bounds.

1.2F1F2F3F4algebra

Fix [β0,β1]⊂(0,∞). Since ∣−A/∣q∣∣≤A/r0, for every integer j≥0 a finite constant Bj gives ∣h(q,p)∣je−βh(q,p)≤Bj(1+∣p∣2j)e−β0∣p∣2/(2μ). This is integrable on Q×R3 by [F2] and [F3], independently of β in the compact interval. The integrand derivatives are (−h)je−βh, so [F4] applied successively proves all moment and derivative formulas.

2.1F3F4step 1.1step 1.2algebra∎

The first two derivatives are Zrel′=−∫he−βhdν and Zrel′′=∫h2e−βhdν. Dividing by Zrel>0 and differentiating the quotient gives d⟨h⟩β/dβ=−⟨h2⟩β+⟨h⟩β2=−Var⁡β(h). Since dTK/dβ=−1/(kBβ2), the chain rule yields the displayed CK≥0.

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