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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Ideals and quotients of semisimple Lie algebras

Statement

Every ideal and every quotient of a finite-dimensional semisimple characteristic-zero Lie algebra is semisimple. More precisely, relative to a decomposition into simple ideals, every ideal is the sum of a subfamily of the simple factors and has an ideal complement.

Facts & Assumptions

Given: A decomposition g=g1⊕⋯⊕gm into simple ideals and an ideal a⊲g.

[L1]

Such a finite decomposition exists (Semisimple Lie algebras decompose into simple ideals).

[L2]

Quotients by ideals carry the published quotient bracket (Quotient Lie algebras).

Proof

technique · factorwise bracketing
1.1L1algebra

Let pi be projection to gi. If pi(a)≠0, simplicity and nonabelianness give [gi,pi(a)]=gi. But bracketing an element supported in the ith factor with an element of a produces an element of a supported only in that factor. Hence gi⊆a. If the projection is zero, the factor does not occur. Therefore a is exactly the direct sum of the factors for which its projection is nonzero.

2.1L1L2step 1.1

The sum of the remaining factors is an ideal complement b, so g=a⊕b. Both a and b are direct sums of simple ideals and hence semisimple. By [L2], projection restricts to an isomorphism b≅g/a, so the quotient is semisimple as well.

3.1step 1.12.1∎

For g=0, the indexing family and both subfamilies are empty; the ideal and quotient are zero. The cases a=0 and a=g correspond to the empty and full subfamilies and are included in step 2.1.

Depends on

Dependency tree · 2 levels

Sources