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Finite relative entropy equals modular energy minus entropy

Statement

Let H be a nonzero finite-dimensional complex inner-product space. Let ρ,σ:H→H be self-adjoint linear maps with nonnegative eigenvalues and trace one, and suppose every eigenvalue of σ is strictly positive. Define Kσ:=−log⁡σ by spectral calculus, and for any self-adjoint τ:H→H with nonnegative eigenvalues and trace one define s(τ):=−tr⁡(τlog⁡τ)=−∑λj(τ)>0λj(τ)log⁡λj(τ), with the zero-eigenvalue term 0log⁡0:=0 and natural logarithms, so the entropy is in nats. Define the modular-energy difference relative to σ by ΔK(ρ,σ):=tr⁡((ρ−σ)Kσ). Then

D(ρ∥σ)=ΔK(ρ,σ)−(s(ρ)−s(σ)).

For any nonzero finite-dimensional complex inner-product spaces HA,HB with H=HA⊗HB, partial tracing both states over HB cannot increase relative entropy:

D(Tr⁡Bρ∥Tr⁡Bσ)≤D(ρ∥σ).

The identity and inequality are finite-dimensional mathematical statements; no Hamiltonian, physical energy, physical units, continuum limit, or gravitational entropy is assumed.

Facts & Assumptions

Given: A nonzero finite-dimensional complex inner-product space H and self-adjoint ρ,σ:H→H with nonnegative eigenvalues and trace one, with σ having strictly positive eigenvalues.

[F1]

Finite-dimensional quantum relative entropy: for nonnegative endomorphisms A,B, if supp⁡(A)⊆supp⁡(B) then D(A∥B)=tr⁡(Alog⁡A)−tr⁡(Alog⁡B) using spectral logarithms on positive supports; otherwise D(A∥B)=+∞.

[F2]

Finite-dimensional von Neumann entropy defines the von Neumann entropy S(τ)=−tr⁡(τlog⁡τ) for a finite-dimensional density endomorphism using the natural logarithm. The function s in the Statement is the same finite spectral sum, written with lowercase s and the convention 0log⁡0:=0.

[F3]

The basis-independent trace of an endomorphism of a finite-dimensional vector space: tr⁡(T) is the basis-independent trace of a finite-dimensional endomorphism, given by the sum of diagonal matrix entries in any basis; it is linear by this finite-sum definition.

[F4]

Partial trace over a finite tensor factor: for nonnegative R on HA⊗HB, the partial trace Tr⁡BR is the endomorphism of HA whose product-basis entries are (Tr⁡BR)ii′=∑jR(i,j),(i′,j).

[F5]

Partial-trace data processing for finite quantum relative entropy: for nonnegative A,B on a finite tensor product HA⊗HB, D(Tr⁡BA∥Tr⁡BB)≤D(A∥B).

Proof

1.1givenF1F2algebra

Since σ has only positive eigenvalues, supp⁡(σ)=H and hence supp⁡(ρ)⊆supp⁡(σ). By [F1], D(ρ∥σ) is finite and equals tr⁡(ρlog⁡ρ)−tr⁡(ρlog⁡σ)=−s(ρ)+tr⁡(ρKσ).

2.1F2F3step 1.1algebra

By [F2] and Kσ=−log⁡σ, s(σ)=tr⁡(σKσ). Linearity of trace [F3] then gives ΔK(ρ,σ)−(s(ρ)−s(σ))=tr⁡(ρKσ)−tr⁡(σKσ)−s(ρ)+s(σ)=tr⁡(ρKσ)−s(ρ)=D(ρ∥σ) by step 1.1. This proves the finite modular-energy identity.

3.1givenF4F5step 2.1algebra∎

With the finite identity established in step 2.1, apply [F5] for the separate partial-trace claim to the nonnegative endomorphisms ρ,σ on HA⊗HB, with the partial trace defined in [F4], to obtain the displayed inequality.

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