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TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passverified 2026-11-05 (gpt-6.1-sol)
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An explicit logarithmic triplet module and a nonsplit submodule extension

Statement

Fix an integer p≥2. Let L=Zα with ⟨α,α⟩=2p, and use the explicit oscillator, trivial-cocycle and square-zero lattice conventions below. Let W(p)⊂VL be the vertex subalgebra generated by ω=(α−12/(4p)+(p−1)α−2/(2p))1, F=e−α, H=QF, and E=Q2F, where Q=(eα)(0). Set v=e−α/p and M=VL+α/2⊕VL+α/2−α/p,Y~(a,z)=YM(a,z)+∑n≥1(−1)n+1nz−nYM(v(n)a,z). Then these fields give an actual admissible W(p)-module action on M. Its cyclic submodule P+p−1=W(p)eα/2 is grading-restricted generalized and logarithmic. Writing h=(2−p)/4, its lowest generalized conformal-weight space has basis u=eα/2, w=eα/2−α/p with L~(0)u=hu+w and L~(0)w=hw. The cyclic submodule M1=W(p)e−α/2 lies in P+p−1 and fits into a nonsplit short exact sequence of admissible W(p)-modules 0⟶Λ(p−1)⟶M1⟶Π(1)⟶0. Here the endpoint modules use the undeformed lattice actions: Λ(p−1)=W(p)eα/2−α/p in VL+α/2−α/p and Π(1)=W(p)e−α/2 in VL+α/2. The injection identifies Λ(p−1) with the corresponding cyclic submodule in the second summand of the deformed module. The quotient map is the restriction to M1 of projection onto the first summand, with image Π(1). All three terms use the common admissible grading d=wt⁡−h inherited from the two lattice summands; in particular Π(1) first occurs in degree p−1, without resetting its bottom degree to zero. The operator L~(0) is semisimple on M1; the Jordan block asserted above is in P+p−1.

Facts & Assumptions

Given: The explicit rank-one lattice data for p≥2 and the module/endpoint conventions in the Statement. Put N=p−1, h=(2−p)/4, t=e−α/2, z=Qt, w=eα/2−α/p, B0=VL+α/2−α/p, and N2=W(p)w. Every degree is the inherited weight minus h.

[F1]

Rank-one lattice and square-zero screening data for the triplet construction defines the original actual fields, deformed cyclic spaces and undeformed endpoints. Explicit rank-one square-zero lattice fields gives the earlier generic square-zero lattice spaces and the complete exponential and normal-order formulas used by the boundary and endpoint suppliers.

[F2]

Admissible triplet action and the Jordan top of the cyclic logarithmic module proves the full deformed module action, its finite nonnegative grading, the actual Jordan top of P+, the inclusion M1⊂P+ and semisimplicity of the conformal zero mode on M1.

[F3]

Screening coefficient and nonsection obstruction for the actual triplet projection proves N2⊂M1, that the actual projection has image the undeformed cyclic Π(1) and kernel M1∩B0, and that this projection admits no admissible section. Its explicit coefficient is Cp=2pp−1(−1)p−1(2p−2p−1)≠0; this nonsection result does not assume the kernel identity to be proved here.

[F4]

The actual two-dimensional triplet zero-mode plane modulo the endpoint proves z∈M1 and that the independent degree-N classes of t,z in M1/N2 span exactly the space generated from tˉ under the zero modes of ω,F,H,E.

[F5]

Simple triplet endpoints and the actual lattice quotient proves the actual cyclic endpoint identifications and irreducibility. It proves B0/N2 simple with lowest degree N and a two-dimensional lowest space, and proves those same lowest-space facts for the actual Π(1).

[F6]

Four triplet fields strongly generate the complete singular span proves that the four-generator algebra in the Statement is strongly generated by those same four homogeneous states.

[F7]

Strong generators generate the lowest space of a cyclic module proves directly from module Jacobi and strong generation that the lowest space of a cyclic admissible module generated there is generated by the strong generators' zero modes.

Proof

1.1givenF1F2F5F6F8

Between the two data models in [F1], send each polynomial charge vector fetα in a specified sector to the vector with the same polynomial, charge and sector. This is a linear isomorphism on the algebra and module spaces. The oscillator multiplications and derivatives, charge shifts and their zero products, zero-mode powers, scalar cocycle 1, and every summand of the finite normal-order rule agree. Thus it intertwines every coefficient of the state and module fields. It fixes the displayed conformal state and v, intertwines Q, and carries F,H,E and their generated vertex subalgebra to the corresponding original ones. Therefore [F5]–[F6] apply to exactly the original algebra and ordinary lattice endpoints in the Statement. Apply [F2] to the actual data [F1]. It supplies the complete Jacobi action, admissible grading and finite generalized conformal-weight spaces. Its degree-zero space in P+ is exactly Ceα/2⊕Cw, with conformal zero-mode action (L~(0)−h)eα/2=w and (L~(0)−h)w=0. This is a nonzero Jordan block, so P+ is logarithmic in [F8]. The same supplier proves that the actual M1 is a submodule of P+ and its conformal zero mode is semisimple.

1.2F3F5F8algebra

By [F3], N2⊂M1 and projection onto the first summand gives a surjective graded homomorphism π:M1→Π(1) with kernel K=M1∩B0. Put R=M1/N2 and J=K/N2. The induced sequence 0→J→R→Π(1)→0 is exact in every inherited degree, and J embeds as a submodule of the ordinary B0/N2. Both B0/N2 and Π(1) have no degrees below N by [F5], so exactness gives R(d)=0 for d<N.

2.1F4F6F7step 1.2algebra

The actual quotient R is cyclic on tˉ in degree N. Reindex R(N+r) by r≥0 and apply [F7], using [F6] for actual strong generation. Thus all of R(N) is generated by the four indicated zero modes on tˉ. By [F4] that generated subspace is exactly the two-dimensional span of tˉ,zˉ: writing A=(3p−2p−1)≠0, its actions are o(F)tˉ=0, o(F)zˉ=Atˉ, o(H)tˉ=−Atˉ, o(H)zˉ=Azˉ, o(E)tˉ=−2Azˉ, o(E)zˉ=0, and o(ω)=(h+N)I. Therefore dim⁡R(N)=2.

3.1F5step 1.2step 2.1algebra

Simplicity of B0/N2 in [F5] says that its submodule J is zero or the whole module. In the latter case dim⁡J(N)=2. The degree-N part of the exact sequence in step 1.2 is a short exact sequence of finite-dimensional vector spaces, and [F5] gives dim⁡Π(1)(N)=2. It would force dim⁡R(N)=2+2=4, contradicting step 2.1. Hence J=0 and K=N2. This proves exactly the kernel equality, rather than only the inclusion of the cyclic endpoint in that kernel.

4.1F2F3F5F8step 1.1step 3.1algebra∎

It follows that the original sequence 0→Λ(p−1)=N2→M1→πΠ(1)→0 is short exact, with the actual simple endpoint identifications from [F5]. This is precisely the projection studied in [F3], which has no admissible section; consequently the sequence is nonsplit. The proof there uses the explicit nonzero value E~(3p−3)t=Cpw and the vanishing of that mode on every possible second-sector correction to a degree-N lift, and requires no Jordan block on M1. All maps retain the common grading, so the quotient's bottom stays in degree N. Together with step 1.1 this proves every assertion of the Statement with the stated module conventions.

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