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Perfect-fluid exchange projections and conduction heating

Statement

Let Ω be an open subset of Smooth formal matter, EM tensors and observer quantities. Let ϵ,p,σ∈C1(Ω,R) and let U∈C2(Ω,TΩ) be future timelike with g(U,U)=−c2. Set

Tmab=ϵ+pc2UaUb+pgab,ab=Ua∇aUb,D=Ua∇a,θ=∇aUa,hbc=δbc+UbUcc2.

For a current ja=σUa+qa with qaUa=0, define fb=Fbcjc and assume the mathematical exchange equation ∇aTmab=fb. Then it is equivalent to the longitudinal and rest-space equations

Dϵ+(ϵ+p)θ=−Ubfb,ϵ+pc2ab+hba∇ap=hbcfc.

The rest electric field of U is EUa=FabUb. If qa=χEUa for a specified scalar χ≥0, then the electromagnetic contribution to the comoving energy balance is −Ubfb=χ g(EU,EU)≥0. For q=0 it is zero. The Ohmic relation is an additional constitutive hypothesis; no equation of state, entropy law, or fluid existence result follows.

Facts & Assumptions

Given: The fields and regularity in the Statement, g(U,U)=−c2, qaUa=0, and ∇aTmab=fb.

[F1]

Smooth formal matter, EM tensors and observer quantities: Tmab=(ϵ+p)UaUb/c2+pgab and EUa=FabUb.

[F2]

Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields: ∇ is metric-compatible and its induced tensor derivative commutes with contractions and annihilates g.

[F3]

Product connection on tensor and hom bundles: the induced tensor connection obeys the Leibniz rule on tensor products and on scalar multiples of tensor fields.

[F4]

The observer rest-space decomposition and the spatial projection: for every future unit timelike vector n, the rest space n⊥ has positive-definite restricted metric.

[A1]

The current is the stated sum ja=σUa+qa with qaUa=0; no constitutive law is assumed until the final conditional clause.

Proof

1.1F1F2F3algebra

Apply the product rule to the three factors of Tmab and use ∇agab=0. The result is ∇aTmab=Ubc2[D(ϵ+p)+(ϵ+p)θ]+ϵ+pc2ab+∇bp.

2.1F2step 1.1algebra

Contract this expression with Ub. The normalization gives UbUb=−c2 and Ubab=12D(g(U,U))=0; also Ub∇bp=Dp. Hence Ub∇aTmab=−Dϵ−(ϵ+p)θ. Equating this with Ubfb proves the longitudinal equation.

3.1F1F2step 1.1step 2.1algebra

The map hbc=δbc+UbUc/c2 satisfies hbcUc=0 and hbcac=ab, by U⋅U=−c2 and U⋅a=0. Applying it to step 1.1 removes the term proportional to Ub and gives the stated rest-space equation.

4.1F1F2F3step 1.1step 2.1step 3.1algebra

For any vector wb, wb=hbcwc−Ub(Ucwc)/c2. Thus if both displayed projected equations hold, the projections of ∇aTmab−fb onto U and U⊥ vanish, so that vector is zero. This proves the converse.

5.1F1F4A1step 2.1algebra∎

Antisymmetry of F gives UbFbcUc=0, so EUa=FabUb is orthogonal to U. Since c>0, n:=U/c is future unit timelike and EU∈n⊥; [F4] makes g(EU,EU)≥0. Therefore −Ubfb=−UbFbcqc=g(EU,q). If q=χEU with χ≥0, this is χg(EU,EU)≥0; if q=0 it is zero. No sign or heating claim has been used without the stated current hypothesis.

Remarks

  • The source-free and charged cases share the same projection identities. A general conduction current is not assumed to obey Ohm's law; Example Explicit local conduction-energy calculation ↗ supplies a local explicit instance of the optional q=χEU branch.
  • These equations are algebraic projections of a supplied balance law, not a global fluid evolution theorem.

Depends on

Dependency tree · 2 levels

Sources