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Smooth vorticity identities and two-dimensional norms

Statement

Assume Countable Choice. Let d∈{2,3}, let s≥4 be an integer, let ν≥0, and let u:[0,T]×Qd→Rd be a smooth real solution of ut+(u⋅∇)u=−∇π+νΔu, ∑j∂juj=0, where Qd=Rd/(2πZ)d has normalized measure and π is a smooth periodic scalar. For d=3, define ω=∇×u by ωi=∑j,k=13ϵijk∂juk, where ϵ123=1 and ϵijk is totally antisymmetric; define (a×b)i=∑j,k=13ϵijkajbk. Then ωt+u⋅∇ω=(ω⋅∇)u+νΔω. For d=2, define the scalar ω=∂1u2−∂2u1; then ωt+u⋅∇ω=νΔω and 12ddt∥ω(t)∥L22=−ν∥∇ω(t)∥L22. For every ν≥0 the scalar maximum bound ∥ω(t)∥L∞≤∥ω(0)∥L∞ holds. These are exact identities and bounds on the given solution lifespan and assert no global existence or regularity result.

Facts & Assumptions

Given: Countable Choice, d,s,ν as in the Statement, and the smooth periodic solution on [0,T].

[A1]

Countable Choice: every countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)).

[F1]

Local smooth periodic Euler and Navier–Stokes: under Countable Choice, smooth divergence-free data on the normalized periodic torus give a unique local smooth solution of the stated incompressible equation for each fixed ν≥0.

Proof

1.1givenA1F1algebra

In dimension three, set u×ω using the usual Levi-Civita component formula. Since div⁡u=0, the identity u⋅∇u=∇(∣u∣2/2)−u×ω and the component expansion ∇×(u×ω)=u div⁡ω−ω div⁡u+(ω⋅∇)u−(u⋅∇)ω give ∇×(u⋅∇u)=(u⋅∇)ω−(ω⋅∇)u. Taking the curl of the momentum equation annihilates the pressure gradient and commutes with ∂t and Δ, yielding the stated 3D equation.

2.1givenstep 1.1algebra

In dimension two, regard u=(u1,u2,0) and ω=(0,0,∂1u2−∂2u1). The 3D curl identity from step 1.1 applies to these fields, and (ω⋅∇)u=0 because u is independent of the third coordinate. Its third component is therefore the stated scalar transport-diffusion equation.

3.1givenstep 2.1algebra

Multiply the scalar equation in step 2.1 by ω and integrate over the periodic torus. The transport integral is 12∫u⋅∇(ω2) dμ=0 by periodicity and div⁡u=0; integration by parts gives ∫ωΔω dμ=−∥∇ω∥22. This proves the enstrophy identity.

4.1givenstep 2.1algebra∎

Set M=∥ω(0)∥∞. For ε>0, the function g(t,x)=ω(t,x)−M−εt is nonpositive at t=0. If it has a positive maximum on the compact cylinder [0,T]×Q2, it occurs at some t∗>0; there ∇g=0, Δg≤0, and the time derivative from the left is nonnegative. But the equation in step 2.1 gives gt+u⋅∇g=νΔg−ε<0, a contradiction. Apply the same argument to −ω, then let ε↓0 to obtain ∥ω(t)∥∞≤M.

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