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LemmaStatement: AI-generatedProof: AI-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A finite connected component gives the opposite relative chamber

Statement

Let (W,S) be a Coxeter system with finite generating set S, in its canonical real representation and dual chamber arrangement, and fix J⊆S. Let (x,I)∈Cham(J) and a∈S∖I with finite WD, where D=[I,a]. Set L=I+a:=I∪{a}, b=ιD(a), K=L∖{b}, and v=wD∖{a}wD. Then (xv,K)∈Cham(J), its chamber has the closed facet xCL‾, and it lies on the opposite side of its supporting hyperplane from xCI. If this facet is the wall of a specified adjacent chamber, that chamber has label (xv,K).

Facts & Assumptions

[F1]

Component opposition gives the simple-root bijection, fixes CL, and gives the strict opposite-side evaluation, by Component opposition transports the retained simple roots.

[F2]

The algebraic label conditions are Algebraic chamber-label set and their geometric bijection is Labelling theorem for relative chambers.

[F3]

Positive images of simple roots are equivalent to absence of right descents, by The root-length criterion and faithfulness of the canonical reflection representation; absence of right descents indexed by a subset is equivalent to minimality in the left coset of the form xWI, by Support, intrinsic parabolic presentations, minimal coset representatives and length additivity, with the type-A identification, part (3).

[F4]

Chamber facets are translated coordinate faces, by Convexity, stratification and faces of the relative cone.

[F5]

The component D=[I,a] is defined by Connected component notation [I,a]. The longest elements and opposition permutation are defined by Longest parabolic elements and opposition permutation for every finite standard parabolic, including the empty one. Since WD∖{a}≤WD, both longest elements used in v are defined.

[F6]

Walls are codimension-one intersections of chamber closures with arrangement hyperplanes; distinct chambers are adjacent when they share a wall, by Chambers, walls and adjacency.

Proof

Given: The finite-rank canonical Coxeter representation, root basis and dual action, with the notation and hypotheses in the Statement. Goal: prove the stated assertions.

Proof technique: direct.

1.1F1F2F3F5

Both longest elements in v are defined by [F5]. Since x is minimal in xWI, [F3] gives xαi∈Φ+ for every i∈I. The bijection in [F1] therefore gives xvαk∈Φ+ for every k∈K. A second application of [F3] shows that xv is minimal in xvWK. Conjugation by v carries each generating reflection indexed by K to a generating reflection indexed by I, bijectively, since it carries their simple roots bijectively. Hence vWKv−1=WI. It follows that xvWK(xv)−1=xWIx−1=WJ. Both label conditions hold.

2.1F1F2F4step 1.1

By [F2] this label represents the relative chamber xvCK. Its facet at b is xvCK+b=xvCL=xCL by [F1, F4]. The same face is the facet at a of xCI. For f∈CK, the functional xvf has negative value on xαa by [F1], whereas every point of xCI has positive value there. Thus the two labelled chambers have the claimed common closed facet and opposite sides.

3.1F2F4F6step 2.1∎

Use the wall and adjacency convention in [F6]. For a facet of a chamber orthant, choose a point in its relative interior that belongs to the arrangement domain. In a sufficiently small neighbourhood, the only active chamber inequality is its facet inequality. Consequently at most one chamber on each side can have that whole facet: two would overlap in an open half-neighbourhood. Applied to the specified adjacent chamber and the chamber in step 2.1, this proves equality on the opposite side. Label uniqueness in [F2] then proves the final assertion. This argument is needed only when the facet is an actual adjacency wall inside the domain.

Depends on

Used by · 3

Dependency tree · 2 levels

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