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A finite connected component gives the opposite relative chamber
Statement
Let be a Coxeter system with finite generating set , in its canonical real representation and dual chamber arrangement, and fix . Let and with finite , where . Set , , , and . Then , its chamber has the closed facet , and it lies on the opposite side of its supporting hyperplane from . If this facet is the wall of a specified adjacent chamber, that chamber has label .
Facts & Assumptions
Component opposition gives the simple-root bijection, fixes , and gives the strict opposite-side evaluation, by Component opposition transports the retained simple roots.
The algebraic label conditions are Algebraic chamber-label set and their geometric bijection is Labelling theorem for relative chambers.
Positive images of simple roots are equivalent to absence of right descents, by The root-length criterion and faithfulness of the canonical reflection representation; absence of right descents indexed by a subset is equivalent to minimality in the left coset of the form , by Support, intrinsic parabolic presentations, minimal coset representatives and length additivity, with the type-A identification, part (3).
Chamber facets are translated coordinate faces, by Convexity, stratification and faces of the relative cone.
The component is defined by Connected component notation [I,a]. The longest elements and opposition permutation are defined by Longest parabolic elements and opposition permutation for every finite standard parabolic, including the empty one. Since , both longest elements used in are defined.
Walls are codimension-one intersections of chamber closures with arrangement hyperplanes; distinct chambers are adjacent when they share a wall, by Chambers, walls and adjacency.
Proof
Given: The finite-rank canonical Coxeter representation, root basis and dual action, with the notation and hypotheses in the Statement. Goal: prove the stated assertions.
Proof technique: direct.
Both longest elements in are defined by [F5]. Since is minimal in , [F3] gives for every . The bijection in [F1] therefore gives for every . A second application of [F3] shows that is minimal in . Conjugation by carries each generating reflection indexed by to a generating reflection indexed by , bijectively, since it carries their simple roots bijectively. Hence . It follows that . Both label conditions hold.
By [F2] this label represents the relative chamber . Its facet at is by [F1, F4]. The same face is the facet at of . For , the functional has negative value on by [F1], whereas every point of has positive value there. Thus the two labelled chambers have the claimed common closed facet and opposite sides.
Use the wall and adjacency convention in [F6]. For a facet of a chamber orthant, choose a point in its relative interior that belongs to the arrangement domain. In a sufficiently small neighbourhood, the only active chamber inequality is its facet inequality. Consequently at most one chamber on each side can have that whole facet: two would overlap in an open half-neighbourhood. Applied to the specified adjacent chamber and the chamber in step 2.1, this proves equality on the opposite side. Label uniqueness in [F2] then proves the final assertion. This argument is needed only when the facet is an actual adjacency wall inside the domain.
Depends on
- Component opposition transports the retained simple roots
- Labelling theorem for relative chambers
- Algebraic chamber-label set
- Convexity, stratification and faces of the relative cone
- The root-length criterion and faithfulness of the canonical reflection representation
- Support, intrinsic parabolic presentations, minimal coset representatives and length additivity, with the type-A identification
- Connected component notation [I,a]
- Longest parabolic elements and opposition permutation
- Chambers, walls and adjacency
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