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LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Component roots intersect the complementary parabolic exactly

Statement

Use the arbitrary-rank geometric representation of Coxeter-system, roots, length and weak-order conventions and the orbit definition ΦL={wαi:w∈WL,i∈L} from Standard parabolic subgroups and parabolic roots. Let I⊆Γ0, a∈Γ0∖I, K=[I,a], J=K∖{a}, VL=span⁡R{αi:i∈L} and D=ΦI+a∖ΦI, with connected-component notation from Connected component notation [I,a]. Vectors have finite support, even if the vertex set is infinite. Then ΦK∩ΦI=ΦJ. In particular ΦK∖ΦJ⊆D. No rank-finiteness assumption is needed.

Facts & Assumptions

Given: the diagram and reflection formula from Coxeter-system, roots, length and weak-order conventions, the root orbits from Standard parabolic subgroups and parabolic roots, and the component K=[I,a] from Connected component notation [I,a]. Put L=I∖K. [F1] There is no edge between K and L; hence B(αk,αl)=0 and sksl=slsk for k∈K,l∈L. [F2] The subspaces VK and VL have zero intersection, and every root is nonzero because it is the invertible image of a basis vector.

Proof

Goal: Establish the assertion in the Statement.

Proof technique: direct.

1.1F1given

The two disjoint parts of I are J and L. By [F1] every finite word in I can be reordered to a word in J followed by a word in L. Generators in L act identically on VK, and generators in J act identically on VL, by the reflection formula. Consequently the orbit under WI of a simple root indexed by J is exactly its orbit under WJ; the orbit of a simple root indexed by L stays in VL. Thus ΦI=ΦJ∪ΦL, with ΦJ⊆VK and ΦL⊆VL.

2.1F2step 1.1given∎

Every root in ΦK lies in VK, because its generators preserve VK. By [F2] and step 1.1, a root belonging also to ΦI must lie in ΦJ. Conversely J⊆K∩I gives ΦJ⊆ΦK∩ΦI directly from the orbit definitions. This proves equality. Finally ΦK⊆ΦI+a, so a root in ΦK∖ΦJ is outside ΦI by the equality and hence lies in D.

Depends on

Used by · 1

Dependency tree · 2 levels

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