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Simplified wall crossing for a finite parabolic

PDF p. 11: Lemma 3.20(4); (3.21)

Statement

Let (W,S) be a Coxeter system indexed by the vertices Γ0 of its Coxeter diagram, let J⊆Γ0, and let (x,I) be a chamber label: WJx=xWI and x has minimum length in xWI. Choose a∈Γ0∖I and put K=I∪{a}. Suppose WK is finite. For a finite parabolic WL, write wL for its longest element and ιL for its opposition permutation, characterized by wLαi=−αιL(i) for i∈L.

With the simple wall-crossing element va,I and pair ωa,I(x,I) defined in Simple wall-crossing elements and maps, one has va,I=wIwK and ωa,I(x,I)=(xwIwK,K∖{ιK(a)}).

Facts & Assumptions

[F1]

The simple crossing is defined by va,I=wD∖{a}wD and ωa,I(x,I)=(xva,I,K∖{ιD(a)}). Simple wall-crossing elements and maps

[F2]

A finite standard parabolic has a finite indexing set; the restricted Coxeter system has its ambient length, and its geometric representation agrees with the ambient representation on the span of its simple roots. Finite-generator standard parabolics and the Bruhat subword property at arbitrary rank Coxeter-system, roots, length and weak-order conventions

[F3]

For a finite-rank Coxeter system, longest elements factor over diagram components, those factors commute, and common components cancel in the product of longest elements. Finite parabolic longest elements and disconnected factors

[F4]

For a finite parabolic, the longest element sends each simple root to the negative of the simple root indexed by its opposition permutation. Longest parabolic elements and opposition permutation

Proof

Given: The Coxeter system, chamber label, vertex a, and finite parabolic WK in the Statement. Put D=[I,a], the component containing a of the diagram induced on K, and put H=K∖D.

Proof technique: direct.

Goal: Prove the two displayed formulas in the Statement.

1.1F1F2F3

Since WK is finite, [F2] makes K finite and permits application of [F3] to the Coxeter system on K. The set H is a union of components of the diagram induced on K. It is also a union of components of the diagram induced on I: deleting a cannot create an edge from H to D∖{a}, and the components contained in H are unchanged. Since I∖H=D∖{a} and K∖H=D, the cancellation formula in [F3] gives wIwK=wD∖{a}wD=va,I. All the displayed parabolics are finite subgroups of WK.

2.1F1F2F3F4step 1.1∎

By the component factorization in [F3], wK=wHwD. There are no diagram edges between H and D, so the defining reflection formula fixes every simple root indexed by D under every generator indexed by H. In particular, using [F4], wKαa=wH(−αιD(a))=−αιD(a). The simple roots are distinct basis vectors, so comparison with wKαa=−αιK(a) yields ιK(a)=ιD(a). Substituting this equality and step 1.1 into [F1] gives the asserted formula for ωa,I(x,I).

Depends on

Used by · 4

Dependency tree · 2 levels

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