Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A second-moment bound for the absence of low-degree vertices

Statement

In G(n,p) with n≥2 and 0<p<1, let k be an integer, let X count vertices of degree at most k, and set a=P(Bin⁡(n−2,p)≤k) and r=P(d(u)≤k). If a>0, then r≥(1−p)a>0 and P(X=0)≤1nr+2p(1−p)2. This does not assume that the full vertex degrees are independent.

Facts & Assumptions

[F1]

Distinct unordered edge indicators are independent (The Erdős-Rényi finite random graph G(n,p)).

[F2]

Joint probabilities factor over disjoint coordinate blocks in a finite product (The finite product of finite probability spaces).

[F3]

Event probabilities are finite sums of outcome weights (Finite probability spaces, outcome weights, events, and event probabilities), and expectations are finite weighted sums (Expectation of a real random variable on a finite probability space).

[F5]

A binomial variable is a sum of independent Bernoulli trials; for zero trials it is the constant zero variable (Bernoulli random variables and binomial random variables as sums of independent Bernoulli trials).

[F6]

Variance is Var⁡X=E[(X−EX)2] (Variance, standard deviation, and covariance on a finite probability space).

[F7]

For an event A, its indicator 1A is 1 on A and 0 outside A (The indicator random variable of an event).

Proof

Given: The objects and hypotheses in the Statement.

Goal: Prove its conclusions.

1.1F1F2F3F4F5givenalgebra

For two distinct vertices u,v, condition on their shared edge. All their other incident edge-coordinate blocks are disjoint. Put b=P(Bin⁡(n−2,p)≤k−1), so 0≤b≤a. Factoring and summing the two shared-edge outcomes gives r=(1−p)a+pb and P(d(u)≤k,d(v)≤k)=(1−p)a2+pb2≤a2. In particular r≥(1−p)a.

2.1F3F4F6F7step 1.1algebra∎

Let Iu be the indicator of degree at most k, so X=∑uIu. Expand the finite sums for EX and EX2 to obtain EX=nr and Var⁡X≤nr+n(n−1)(a2−r2)≤nr+2pn2a2, since a2−r2≤[1−(1−p)2]a2≤2pa2. On X=0, (X−EX)2=(nr)2, so the nonnegative expectation sum gives P(X=0)≤Var⁡X/(nr)2. Insert the variance estimate and r≥(1−p)a to get the displayed bound.

Depends on

Used by · 1

Dependency tree · 2 levels

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