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LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The gamma-two graph has a vertex of degree at most log n with high probability

Statement

Let n≥3 be an integer, let L=log⁡n (the natural logarithm), p=2L/n, and let G∼G(n,p) on [n]. Write d(u)=deg⁡G(u) and dmin⁡=δ(G)=min⁡u∈[n]d(u). For all sufficiently large such n, P(dmin⁡>⌊L⌋)≤ηn:=2e4Ln+2p(1−p)2,ηn→0. Thus a vertex of degree at most log⁡n occurs with probability tending to one.

Facts & Assumptions

[F1]

Set k=⌊L⌋ and a=P(Y≤k) for Y∼Bin⁡(n−2,p), a sum of n−2 independent Bernoulli-p variables (Bernoulli random variables and binomial random variables as sums of independent Bernoulli trials). For all sufficiently large integers n, a≥e−4n−1/2/L>0 (A logarithmic low-degree atom for the gamma-two graph).

[F2]

Let X count the vertices of degree at most k and set r=P(d(1)≤k). For n≥2, 0<p<1 and a>0, the same a,k,p satisfy r≥(1−p)a>0 and P(X=0)≤1/(nr)+2p/(1−p)2 (A second-moment bound for the absence of low-degree vertices).

[F3]

For every fixed b>0, log⁡n/nb→0 (The logarithm grows more slowly than every positive real power).

[F4]

The model G(n,p) is the finite simple graph on [n] whose distinct edge indicators are independent Bernoulli-p variables, for p∈[0,1] (The Erdős-Rényi finite random graph G(n,p)).

[F5]

Vertex degree counts incident edges; on a nonempty finite vertex set, δ(G) is the minimum vertex degree (Adjacency, incidence, open and closed neighbourhoods, vertex degree, minimum degree and maximum degree).

[F6]

The integer k=⌊L⌋ satisfies k≤L<k+1 (Integer part: for every real x there is exactly one integer m with m ≤ x < m + 1).

[F7]

In a finite probability space, P(Ac)=1−P(A), probabilities are nonnegative and at most one, and A⊆B implies P(A)≤P(B) (Normalization, nonnegativity, monotonicity, complements, and differences in a finite probability space).

Proof

Given: The objects and hypotheses in the Statement.

Goal: Prove its conclusions.

1.1F1F2F3F4F5givenalgebra

Take n sufficiently large that [F1] applies and 0<p<1/2; the latter is possible because L>0 for n≥3 and p=2L/n→0 by [F3]. Thus [F4] defines the graph model, and the hypotheses of [F2] hold for the a,k,r,X fixed in [F1] and [F2]. Since [n] is nonempty, [F5] gives {X=0}={dmin⁡>k}. Moreover nr≥n(1−p)a≥e−4n/(2L). Substitution in [F2] therefore proves P(dmin⁡>k)≤2e4L/n+2p/(1−p)2=ηn.

2.1F3F5F6F7step 1.1algebra∎

By [F3] with b=1/2 and b=1, L/n→0 and p→0, so ηn→0. Set A={dmin⁡>k} and let B be the event that some vertex has degree at most L. By [F5] and [F6], Ac={dmin⁡≤k}⊆B. Applying [F7] and step 1.1 gives 1≥P(B)≥P(Ac)=1−P(A)≥1−ηn→1, proving the final assertion.

Depends on

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