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Finite sieve determines the probability of a zero count
Statement
Let be nonnegative integer-valued random variables on finite probability spaces, and define for integers , and zero for . Powers use natural integer exponents, with also when . If, for each fixed , for a fixed , then . No assertion about other values of is needed.
Facts & Assumptions
Given: The objects and hypotheses of the Statement.
Goal: Prove the Statement.
Expectation is a finite weighted sum, preserving pointwise inequalities (Expectation of a real random variable on a finite probability space).
Factorials and falling factorials have their finite product definitions (The factorial n! and the falling factorial n^k̲, defined by recursion in ℕ).
The exponential is the everywhere convergent series (The real exponential function and the number e by a power series).
Convergence is interpreted along the sequence of finite probability spaces (Asymptotic quantifiers and uniform parameter ranges).
A finite probability space has nonnegative weights summing to one; every subset is an event whose probability is the sum of its weights. A real random variable is a function (Finite probability spaces, outcome weights, events, and event probabilities, Real random variables on finite probability spaces and their finite distributions).
For and , real powers satisfy , and the inverse logarithm satisfies (Real powers for positive bases, with the zero-base positive-exponent convention, The natural logarithm as the inverse of the exponential function).
Natural integer powers satisfy and for every real and integer , including (Integer powers aᵐ).
Proof
For integers and , Pascal's identity, obtained by separating subsets according to whether they contain a specified element, telescopes to ; the binomial coefficient is zero beyond its range. The factorial formula agrees with subset counting because each -subset admits orders. For , the sum is one. Write for the function equal to one when and zero otherwise. Thus, for every , .
On , the function has expectation . Put and . Taking expectations in step 1.1 and distributing the finite weighted sum over the finite sieve sums gives for every .
Put and . The natural-power recursion gives by induction on , starting at with both sides equal to one. Thus by the exponential series, including when . Fix and choose so that both and . For each of the finitely many , the given moment convergence supplies an such that for . For , the triangle inequality gives for both and . The bounds from step 2.1 now imply , so . This proves directly from the convergence definition.
The series at one gives , and the inverse logarithm gives ; hence by the real-power definition. Substituting this identity into step 3.1 yields the stated zero-count limit.
Depends on
- Expectation of a real random variable on a finite probability space
- The factorial n! and the falling factorial n^k̲, defined by recursion in ℕ
- The real exponential function and the number e by a power series
- Asymptotic quantifiers and uniform parameter ranges
- Finite probability spaces, outcome weights, events, and event probabilities
- Real random variables on finite probability spaces and their finite distributions
- Real powers for positive bases, with the zero-base positive-exponent convention
- The natural logarithm as the inverse of the exponential function
- Integer powers aᵐ
Dependency tree · 2 levels
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