Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Uniform degree slack and the vanishing synchrony condition

Statement

Fix 0<ε<1, g>12/ε2, and K>0. Let n≥2 be an integer tending to infinity, 0<p≤1, and G∼G(n,p) on [n]={1,…,n}. Write dmin⁡=min⁡v∈[n]deg⁡G(v) and dmax⁡=max⁡v∈[n]deg⁡G(v). Set μ=np≥glog⁡n and α=K/μ. Uniformly over these p, with probability tending to one, (1−ε+α)μ≤dmin⁡≤dmax⁡≤(1+ε−α)μ. For all sufficiently large n, uniformly in this range, μ>0, 0<α≤1/5, and 32α(1+7ε)(1−ε)2log⁡ ⁣(1+ε+α2α)<1.

Facts & Assumptions

[F1]

The uniform degree bound centered at np is Chernoff bounds with the exact degree mean.

[F2]

For x>0, log⁡x=∫1xdt/t and log⁡′(x)=1/x (The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t). The integral logarithm L is unbounded above (The integral logarithm is unbounded above and below) and satisfies L(x)=log⁡x for x>0 (The integral logarithm L is the published natural logarithm).

[F3]

The independent-edge random graph law is The Erdős-Rényi finite random graph G(n,p). Vertex degree, minimum degree and maximum degree are as in Adjacency, incidence, open and closed neighbourhoods, vertex degree, minimum degree and maximum degree.

Proof

Given: The objects and hypotheses in the Statement.

Goal: Prove all stated conclusions.

1.1F1F2F3givenalgebra

For the graph and degrees in [F3], use [F1] with deviation ε/2, since g>3/(ε/2)2. Except on an event tending uniformly to zero, all degrees are between (1−ε/2)μ and (1+ε/2)μ. By [F2], log⁡ is increasing and unbounded above, hence log⁡n→∞. Thus α≤K/glog⁡n→0 uniformly, so eventually α≤ε/2 and α≤1/5. The claimed bounds follow by inclusion of these intervals. Positivity of μ and α is immediate for these n.

2.1F2step 1.1algebra∎

Put C0=(1+ε+1/5)/2>1/5. For α≤1/5, the logarithm in the Statement is positive and at most log⁡(C0/α). For x≥1, [F2] gives log⁡x=∫1xdt/t≤∫1xdt/t≤2x. Therefore the left side is at most 64(1+7ε)(1−ε)−2C0α, tending uniformly to zero by step 1.1. It is eventually less than one as required.

Depends on

Used by · 1

Dependency tree · 2 levels

Each result is drawn at its shortest distance from this item. Arrows run from prerequisites to the items that use them; this item has a heavier outline. External source nodes link directly to the cited text. The view shows up to two dependency steps; open a prerequisite to continue.