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Degree bounds from two-sided expansion — Lemma 3.1

PDF p. 18: Lemma 3.1

Statement

If G is an (n,d∗,α,c−,c+)-expander, then (1+c−)d∗−d∗/n≤dmin⁡(G)≤dmax⁡(G)≤(1+c+)d∗+1−d∗/n.

Here the expander predicate, including its centered Laplacian inequalities, is as in Two-sided spectral expander — Definition 1.9; degrees and their extrema use Adjacency, degrees, graph Laplacian, and spectral notation. In particular, n>0, the adjacency matrix is binary, and a loop contributes once to its vertex's degree.

Facts & Assumptions

[F1]

For the expander, c−d∗I⪯ΔL⪯c+d∗I, where ΔL=L−d∗I+(d∗/n)J and L=D−A (Two-sided spectral expander — Definition 1.9). The order is the quadratic-form order on Hermitian matrices (Loewner order, Hermitian inner product, and operator norm).

[F2]

The graph has a nonempty finite vertex set V, Dxx=d(x), Axx∈{0,1}, and dmin⁡(G) and dmax⁡(G) are the minimum and maximum of the degrees (Adjacency, degrees, graph Laplacian, and spectral notation).

[F3]

If a Hermitian matrix B satisfies aI⪯B⪯bI, then a≤Bxx≤b for every vertex x (Self-adjoint order, norm bounds and diagonal tests).

Proof

Given: An (n,d∗,α,c−,c+)-expander G.

Goal: Establish the stated chain of degree bounds.

1.1F1F2F3algebra

The matrices in [F1] are real symmetric and hence Hermitian. Applying the diagonal test [F3] to the two inequalities in [F1] gives c−d∗≤(ΔL)xx≤c+d∗ for each x∈V. Since Jxx=Ixx=1, [F1] and [F2] give (ΔL)xx=d(x)−Axx−d∗+d∗/n. Thus (1+c−)d∗−d∗/n+Axx≤d(x)≤(1+c+)d∗−d∗/n+Axx.

2.1F2step 1.1algebra∎

By [F2], 0≤Axx≤1, so every degree lies between (1+c−)d∗−d∗/n and (1+c+)d∗+1−d∗/n. Taking the minimum and maximum over the nonempty finite set V yields the outer bounds, while the minimum is at most the maximum. This proves the displayed chain.

Source notes

The statement is attributed to Lemma 3.1 of Expander graphs are globally synchronizing; the argument above rests on the stated mathematical suppliers.

Depends on

Used by · 1

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Sources