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Disjoint-set lower mixing needs additional hypotheses

PDF p. 20: Paragraph before Lemma 3.7

Statement

A positive multiplicative lower estimate e(X,Y)≥ε(d∗/n)∣X∣∣Y∣ need not hold for every pair of disjoint vertex sets in a two-sided spectral expander. Indeed, the four-cycle is a (4,2,1,0,1)-expander and has two disjoint singleton sets X,Y for which e(X,Y)=0. Thus every ε>0 fails for these sets. Here the four-cycle has vertices 1,2,3,4 and edges {1,2},{2,3},{3,4},{4,1}; its two-sided parameters mean the centered adjacency norm is at most αd∗ and the centered Laplacian lies between c−d∗I and c+d∗I in quadratic-form order.

Facts & Assumptions

[F1]

For a graph with adjacency matrix A, degree matrix D, Laplacian L=D−A, and all-ones matrix J, the centered matrices are ΔA=A−(d∗/n)J and ΔL=L−d∗I+(d∗/n)J. The expander conditions are the norm and quadratic-form inequalities stated above (Two-sided spectral expander — Definition 1.9, Adjacency, degrees, graph Laplacian, and spectral notation).

[F2]

The ordered edge count is e(X,Y)=∑x∈X∑y∈YAxy (Oriented edge count between sets).

[F3]

Cauchy–Schwarz bounds ∣v∗z∣ by ∥v∥2∥z∥2, and the operator norm is the maximum of ∥Bz∥2 over unit vectors z (Cauchy–Schwarz: |⟨ u,v⟩|≤‖ u‖‖ v‖, with equality exactly for linearly dependent vectors, The operator norm is zero on the zero domain and otherwise is max_‖ v‖=1‖ Tv‖).

Proof

Given: The four-cycle and its vertex ordering as in the statement.

Goal: Verify the expander parameters and exhibit disjoint sets violating the proposed lower estimate.

1.1givenF1algebra

Put v=(1,−1,1,−1)T. Direct inspection of the edges gives A=(J−vvT)/2 and D=2I. With n=4 and d∗=2, the centered-matrix formulas give ΔA=−vvT/2 and ΔL=vvT/2. Also v∗v=4.

2.1F1F3step 1.1

For every complex vector z, Cauchy–Schwarz gives 0≤z∗ΔLz=∣v∗z∣2/2≤2∥z∥22, so 0⪯ΔL⪯2I. Likewise ∥ΔAz∥2=∥v∥2∣v∗z∣/2≤2∥z∥2, giving ∥ΔA∥≤2. These are the required inequalities for (n,d∗,α,c−,c+)=(4,2,1,0,1).

3.1F2step 2.1algebra∎

Take X={1} and Y={3}. They are disjoint and their vertices are not adjacent, so e(X,Y)=A13=0. For every ε>0, the proposed right-hand side equals ε(2/4)∣X∣∣Y∣=ε/2>0. Hence the estimate fails for these sets, despite the verified expander conditions.

Source notes

The observation that additional set assumptions are needed is attributed to the paragraph immediately before Lemma 3.7 in Expander graphs are globally synchronizing. The example and its verification above are local.

Depends on

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