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Exact state evolution from a four-level codeword
PDF p. 8: Eq. (S1.1)
Statement
Assume the four-level model with real , decay rate , and . For a normalized initial code state , its evolved density operator is
where when and at . Here h.c. denotes the Hermitian conjugate of the preceding off-diagonal term. The value at the origin is the continuous extension.
Facts & Assumptions
In the postulated model, , , and the state evolves by the corresponding finite GKSL channel. Four-level spontaneous-decay model
The ordered basis is orthonormal; bras, adjoints and outer products act according to the finite operator conventions. Finite operator and ket conventions
The finite GKSL interface defines for the stated Hermitian Hamiltonian and jump. Finite GKSL evolution and the QEC channel interface
For finite GKSL data, the channel is the sum of the no-jump term and ordered integrals of jump amplitudes, with and . Finite no-jump and ordered-jump expansion
A density operator on a nonzero finite-dimensional complex inner-product space is a non-negative endomorphism with trace one. Density operator
A pure state is a ray, and a unit representative has operator representative . Use this operator representative for the initial code state. Pure state and ray
On a nonzero finite-dimensional complex inner-product space with the root pairing linear in its first argument, the outer product of a unit vector is non-negative and has trace one, hence is a density operator. A unit-vector outer product is a density operator
Proof
Given: The model, normalized , and nonnegative time in the statement.
Goal: Calculate and establish the stated extension.
By [F6], the initial pure code state has operator representative . Its underlying space is with the root pairing linear in its first argument, and the normalized vector is unit. The outer-product action in [F2] is , which agrees with the convention in [F7]. Thus [F7] and [F5] make a density operator. By [F1] and [F3], its physical model evolution is .
By [F1] and [F2], . Thus acts by on both code basis vectors, by on , and by on . In particular, the no-jump contribution in [F4] is .
For , the single-jump amplitude on the initial state is . Its image lies in the span of , which is preserved by and annihilated by . Hence every term with two or more jumps vanishes on the initial density operator. The single-jump diagonal coefficients are and .
The single-jump coefficient is . For , direct integration gives ; the opposite coefficient is its complex conjugate. At the integral is zero, and its absolute value is at most , so this value is continuous as within . Combining the no-jump and single-jump terms gives the displayed density operator.
Depends on
Dependency tree · 2 levels
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Sources
- Monolithic Quantum Error Correction in the Presence of Distinguishability · PDF p. 8, Eq. (S1.1) and opening model paragraph