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Cubic short-time loss and recoverable limits

PDF p. 2: Eq. (5) and following paragraph; PDF p. 8: Eq. (S1.5)

Statement

Assume the four-level model with real ω0,Δ, rate γ≥0, and the syndrome recovery R4. The code has orthonormal basis ∣0⟩,∣1⟩. For a normalized code state ∣ψ⟩=a∣0⟩+b∣1⟩, let Fψ(t) be the branch-averaged decoded state fidelity: the sum of each recovery outcome probability times its conditional output's overlap with ∣ψ⟩, with a zero-probability outcome contributing zero. At fixed parameters, as t→0 through nonnegative times,

1−Fψ(t)=cψγΔ2t3+O(t4),cψ=∣a∣2∣b∣23≤112.

Here O(t4) means a quantity bounded in absolute value by Ct4 for sufficiently small nonnegative t, for a constant C that may depend on the fixed parameters. For positive γ, one power of time comes from the decay probability and two from the relative phase mismatch between decay paths. If γ=0 or Δ=0, the recovered output equals the input for every code density operator at every finite t≥0.

Facts & Assumptions

[F1]

The postulated model has real ω0,Δ, rate γ≥0, and the stated orthonormal code basis; its evolution is a linear channel. Four-level spontaneous-decay model

[F2]

The recovery has null operation X↦PXP and decay operation X↦UXU†, with P=∣0⟩⟨0∣+∣1⟩⟨1∣ and U=∣0⟩⟨2∣+∣1⟩⟨3∣; discarding the outcome sums these operations. Four-level syndrome recovery

[F3]

For γt>0, put p=1−e−γt and χ=γ(eiΔt−e−γt)/[(γ+iΔ)p]. The fidelity is Fψ=1−2∣a∣2∣b∣2p(1−Re⁡χ). At γt=0, it is one. Branch-averaged decoded state fidelity

[F4]

For γt>0, the normalized null output is ∣ψ⟩⟨ψ∣ and the normalized decay output has diagonal entries ∣a∣2,∣b∣2 and off-diagonal entries ab∗χ and its conjugate. At γt=0 the decay branch has zero probability. Conditional decoded state and decay coherence

[F5]

Outer products and adjoints use the finite orthonormal-basis conventions. Finite operator and ket conventions

[F6]

The finite exponential series has a controlled remainder, and products and quotients with nonzero limiting denominator have the stated fixed-parameter expansions. Finite exponential and smooth quotient remainder control

[F7]

On a nonzero finite-dimensional complex inner-product space, every density operator has a finite spectral ensemble ρ=∑j=1mλj∣ej⟩⟨ej∣, where the ej are orthonormal unit vectors, λj>0, and ∑jλj=1. Density operators have an orthogonal spectral ensemble

[F8]

For the normalized code input and every γ≥0, t≥0, the exact evolved operator is ρ(t)=e−γt∣ψ⟩⟨ψ∣+(1−e−γt)(∣a∣2∣2⟩⟨2∣+∣b∣2∣3⟩⟨3∣)+[ab∗c(t)∣2⟩⟨3∣+h.c.], where c(t)=γ(eiΔt−e−γt)/(γ+iΔ) when (γ,Δ)≠(0,0) and c(t)=0 at (0,0); h.c. denotes the Hermitian conjugate of the preceding term. Exact state evolution from a four-level codeword

Proof

Given: The model, recovery, normalized code state, and fixed parameters in the statement.

Goal: Establish the short-time expansion and exact recovered outputs in the two parameter limits.

1.1givenF3F6algebra

Suppose γ>0 and t>0. Set c=γ(eiΔt−e−γt)/(γ+iΔ), so pχ=c. Applying the exponential expansion in [F6] to the scalar exponentials, and using γ+iΔ≠0, gives p=γt−γ2t2/2+γ3t3/6+O(t4) and c=γt+γ(iΔ−γ)t2/2+γ(γ2−iγΔ−Δ2)t3/6+O(t4). Consequently p−Re⁡c=γΔ2t3/6+O(t4).

1.2givenF2F3F4F5F8algebra

If γ=0 and Δ≠0, the expression for c(t) in [F8] has zero numerator and nonzero denominator, so c(t)=0; if also Δ=0, its specified boundary value is zero. Thus [F8] gives ρ(t)=∣ψ⟩⟨ψ∣ at γ=0. By [F2] and [F5], P∣ψ⟩=∣ψ⟩ and U∣ψ⟩=0, so the unnormalized recovered null output is the input projector and the decay output is zero. The loss is identically zero and satisfies the expansion. If Δ=0 and γt>0, [F3] gives χ=1; the two conditional outputs in [F4] then both equal ∣ψ⟩⟨ψ∣. At t=0, [F8] gives c(0)=0 and ρ(0)=∣ψ⟩⟨ψ∣, and the same recovery calculation applies. Summing outcome-weighted outputs therefore restores every pure code state in either limit.

2.1givenF3F6step 1.1algebra

By [F3], 1−Fψ=2∣a∣2∣b∣2(p−Re⁡c), which gives the displayed cubic coefficient. Normalization gives ∣a∣2+∣b∣2=1, so (∣a∣2−∣b∣2)2≥0 implies ∣a∣2∣b∣2≤1/4. Moreover p=γt+O(t2), and division after cancelling t gives 1−Re⁡χ=Δ2t2/6+O(t3). Thus the two factors have the stated time orders.

3.1F1F2F5F7step 1.2step 2.1algebra∎

The evolved-and-recovered map is linear by [F1] and [F2]. Apply [F7] on the code space C=span⁡{∣0⟩,∣1⟩}, a nonzero two-dimensional complex inner-product space by [F1] and [F5]. Every code density operator therefore has an ensemble ρ=∑j=1mλj∣ej⟩⟨ej∣ with unit code vectors ej and positive weights summing to one. In either parameter limit, step 1.2 restores each projector, so linearity gives R4(Nt(ρ))=∑jλj∣ej⟩⟨ej∣=ρ. Together with step 2.1, this proves the exact limits and the expansion for all γ≥0.

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