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LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The exhaustive analytic horizon-component case split

Statement

For a nonempty horizon with its componentwise rotation and degeneracy labels, exactly one of the following cases holds: (R) some component rotates; (N) every component is non-rotating and none is degenerate; (D) every component is non-rotating and at least one is degenerate. Case (D) includes mixed degenerate and nondegenerate components. Multiplying a specified horizon generator by any fixed nonzero constant preserves whether its surface gravity vanishes.

Facts & Assumptions

[F1]

Rotation and normalized surface gravity are Rotation, surface gravity and horizon degeneracy, and component/regularity conventions are Staticity, axisymmetry and black-hole regularity hypotheses. Non-rotation is tangency of T to the generator line everywhere on the specified component. Degeneracy is the zero surface-gravity condition for the supplied Killing generator.

Proof

Given: The componentwise predicates and specified generators.

Goal: Establish exhaustive disjoint cases and normalization invariance.

1.1givenF1

Either some component rotates or none does. In the second alternative all components are non-rotating; either at least one is degenerate or none is. These are mutually exclusive alternatives and yield precisely (R), (D) and (N). No assumption that every component has the same degeneracy type is introduced.

2.1givenF1step 1.1algebra∎

For K′=aK with constant a≠0, the Killing-horizon equation gives ∇K′K′=a2∇KK=aκK′. Thus the new coefficient is aκ, which vanishes exactly when κ does. Also scaling the stationary field by a positive constant does not change its tangency to the same generator lines. The case partition is consequently independent of those constant normalizations.

Depends on

Used by · 2

Dependency tree · 2 levels

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