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Stationary flow-box data for a nonzero Killing field

Statement

Let (M,g,T) be stationary Lorentzian data, so M is a smooth four-manifold and T is a smooth Killing field with LTg=0. On an open neighborhood U of x, let ψ∈C∞(U,R) be a smooth scalar function and W0∈Ω1(U) a smooth real covariant one-form. Assume both are stationary along T, meaning LTψ=0 and LTW0=0 on U.

If Tx≠0, there are local coordinates (t,x1,x2,x3) near x, contained in U, with T=∂t. All coordinate components of g,ψ,W0 are then independent of t, whether Tx is timelike, spacelike or null.

Their stationary two-jets at x mean their values and coordinate derivatives through total order two in this chart, with every derivative involving ∂t equal to zero. In particular, for each component function h of g,ψ,W0, these data are h(x), ∂ah(x) and ∂a∂bh(x) for a,b∈{0,1,2,3}, where x0=t; the second derivatives are symmetric in a,b. This is a chartwise description of the two-jets, not an assertion that component lists are invariant under changes of chart.

Facts & Assumptions

[F1]

The smooth four-manifold, metric, Killing field and local-flow definition of LTg are those of Stationary Lorentzian data and tensor conventions. No timelike or complete-flow hypothesis is part of stationarity here.

[F2]

A smooth k-form is a smooth section of ⋀kT∗U, with Ω0(U)=C∞(U), by A smooth differential k-form. Thus ψ is a scalar and W0 is a covariant one-form, locally W0=(W0)a dxa. Their Lie derivatives use The Lie derivative of a function and The Lie derivative of a tensor field, respectively. The vanishing of both Lie derivatives is an explicit hypothesis, not a consequence of the Killing condition for g.

[F3]

At a nonzero point of a smooth vector field, The flow-box theorem supplies coordinates straightening it to a coordinate vector field; the chart can be restricted to a product neighborhood contained in U.

[F4]

For any smooth covariant k-tensor A and smooth vector field X, The coordinate formula for the Lie derivative of a covariant tensor gives (LXA)i1⋯ik=Xj∂jAi1⋯ik+∑a=1k(∂iaXj)Ai1⋯j⋯ik. For a smooth scalar h, Tensor Lie derivative agrees with X on functions and bracket on vector fields gives LXh=Xh.

[F5]

Coordinate derivatives and their total order use Cᵏ maps and multi-index derivative notation in Euclidean space. Every component here is smooth, hence C2, so Clairaut--Schwarz theorem for continuous second partial derivatives gives ∂a∂bh=∂b∂ah for every component h and all coordinate indices.

Proof

Given: The stationary Lorentzian data, smooth scalar and one-form, vanishing Lie derivatives and nonzero point in the Statement.

Goal: Construct the stated stationary chart and identify its two-jet data.

1.1givenF1F2F3F4

Apply [F3] at x to arrange T=∂t in a product chart contained in U. The components of this vector field are constant, so all terms ∂aTb in [F4] vanish. Applying its covariant-tensor formula to g and W0, and its scalar formula to ψ, gives (LTg)ab=∂tgab, (LTW0)a=∂t(W0)a and LTψ=∂tψ. By [F1] and the stationary-field hypotheses in [F2], these expressions vanish throughout the chart. Thus the components are independent of the product coordinate t.

2.1F5step 1.1∎

For each component function h, differentiate the identity ∂th=0 from step 1.1 in any coordinate direction to obtain ∂a∂th=0. By [F5], ∂t∂ah=∂a∂th=0 as well, including a=0. The same mixed-partial identity makes all second derivatives symmetric. Consequently the component values, first derivatives and second derivatives through total order two are precisely the stationary two-jet data described in the Statement, with all time-containing derivatives zero. The construction required only Tx≠0, so applies also at nonzero null or spacelike points.

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