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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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The flow-box theorem

Statement

Let X be a smooth vector field on M, and let p∈M satisfy Xp≠0. Then there are local coordinates (u1,…,un) near p in which

X=∂∂u1.

Facts & Assumptions

Given: A smooth vector field X and a point p with Xp≠0.

[L1]

The maximal flow of X is smooth on an open domain (The fundamental theorem on flows).

[L2]

The manifold inverse function theorem turns a map with invertible differential into a local diffeomorphism (The smooth inverse function theorem on manifolds).

[L3]

Time-t flow maps are diffeomorphisms between open domains (Time-t flow maps are diffeomorphisms between open domains).

Proof

technique · direct
1.1given

Choose a chart around p in which the first coordinate component of Xp is nonzero, and let S be the codimension-one slice where that first coordinate is constant. Then TpM=RXp⊕TpS.

2.1L1step 1.1

Let Φ be the maximal flow of X and define F(t,q):=Φt(q) for (t,q) near (0,p) with q∈S. By [L1], F is smooth. Its differential at (0,p) sends the time direction to Xp and sends TpS identically into itself, so dF(0,p) is an isomorphism by step 1.1.

3.1L2step 2.1

Applying [L2] to F at (0,p) gives local coordinates (u1,…,un) in which F becomes the identity on an open set of R×Rn−1. In those coordinates, the flow translates the first coordinate, and therefore its generating vector field is ∂/∂u1.

4.1step 3.1L3∎

Hence every nonvanishing point of a smooth vector field has a neighbourhood in which the field is straightened to a coordinate vector field.

Depends on

Used by

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources