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The fundamental theorem on flows

Statement

Let X be a smooth vector field on M. For each pM, let γp:IpM be the maximal integral curve through p, and set

D:={(t,p)R×M:tIp},Φ(t,p):=γp(t).

Then D is open in R×M, each fibre Dp is an interval containing 0, the map Φ:DM is smooth, and Φ is the unique maximal local flow generated by X.

Facts & Assumptions

Given: A smooth vector field X on M.

[L1]

Every point lies on a unique maximal integral curve (Through each point there is a unique maximal integral curve).

[L2]

Integral curves exist uniquely on uniform local time intervals and depend smoothly on the initial point (Local existence, uniqueness, and smooth dependence for manifold integral curves).

Proof

technique · direct
1.1

By [L1], for each pM there is a unique maximal integral curve γp:IpM through p. Therefore the set D and the map Φ(t,p)=γp(t) are well defined, each fibre Dp=Ip is an open interval containing 0, and Φ(0,p)=p.

L1given
1.2

Fix pM and sIp, and put q:=Φ(s,p)=γp(s). Then the translated curve tγp(t+s) is an integral curve through q on the interval Ips:={t:t+sIp}. By uniqueness of maximal integral curves, it agrees with γq on their common domain, so Φ(t,Φ(s,p))=Φ(t+s,p) whenever both sides are defined. The same translation argument applied to γq shows Iq=Ips.

L1L2given
2.1

Let WD be the set of all (t,p)D such that Φ is defined and smooth on some product neighbourhood J×UD of (t,p). By [L2], every (0,p) lies in W. Suppose WD. Choose (τ,p0)DW; replacing τ by τ if needed, we may assume τ>0. Let t0:=inf{tR:(t,p0)W}. Then t0Ip0, because (0,p0)W and Ip0 is an open interval containing τ. Put q0:=Φ(t0,p0). Applying [L2] at q0 gives ε>0 and an open neighbourhood U0 of q0 such that the local flow is smooth on (ε,ε)×U0. Choose t1<t0 with t1+ε>t0 and Φ(t1,p0)U0. Because (t1,p0)W, there is a product neighbourhood (t1δ,t1+δ)×U1W; shrinking U1 if necessary, we may assume Φ({t1}×U1)U0.

L2step 1.1step 1.2chooseassume-contra
3.1

Define Φ~(t,p):={Φ(t,p),0t<t1,Ψ(tt1,Φ(t1,p)),t1ε<t<t1+ε, where Ψ is the local flow from step 2.1. By step 1.2, the two formulas agree on the overlap, so Φ~ is a smooth extension of Φ to a product neighbourhood of (t0,p0). This contradicts the choice of t0. Therefore W=D, so D is open and Φ is smooth.

step 1.2step 2.1constructdischarge-contradiction
4.1

Step 3.1 makes each slice Dt:={p:(t,p)D} open in M. For pDt, step 1.2 gives IΦ(t,p)=Ipt, so tIΦ(t,p) and hence Φ(t,p)Dt. The same step also yields Φ(t,Φ(t,p))=Φ(0,p)=p, and symmetrically Φ(t,Φ(t,q))=q for qDt. Thus Φt:DtDt is a diffeomorphism with inverse Φt.

step 1.2step 3.1
5.1

Steps 1.1-4.1 show that Φ:DM is a smooth local flow whose time slices are exactly the maximal integral curves of X. Any other local flow of X has the same time slices by uniqueness of integral curves, so its domain is contained in D and its map agrees with Φ. Therefore Φ is the unique maximal local flow generated by X.

step 1.1step 1.2step 3.1step 4.1

Depends on

Used by

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Sources