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Moving a sphere off a lower-dimensional submanifold

Statement

Assume ACω. Let A,B⊆V be embedded submanifolds with A compact of a smooth manifold V with dim⁡A+dim⁡B<dim⁡V, and suppose that A has a product neighbourhood in V. Then for every neighbourhood of A there is a diffeomorphism h:V→V, smoothly isotopic to the identity and supported in that neighbourhood, with h(A)∩B=∅. The isotopy may be chosen arbitrarily close to the identity in C∞ on its fixed compact support.

Facts & Assumptions

[A1]

Product neighbourhood. There are an open set U⊆V with A⊆U and a diffeomorphism k:A×Rd→U, where d=dim⁡V−dim⁡A, with k(a,0)=a for every a∈A; such a neighbourhood may be chosen inside any prescribed neighbourhood of A. The product trivialization is a hypothesis; the tubular neighbourhood theorem The tubular neighbourhood theorem in a smooth ambient manifold alone does not assert that the normal bundle is trivial. Compactness of A permits a uniform product tube inside the prescribed neighbourhood.

[F1]

The image of a lower-dimensional C1 manifold is null: Assume the Axiom of Countable Choice. Let Pm and Nn be smooth manifolds with m<n, and let F:P→N be a C1 map. Then F(P)⊆N is a null subset of N.

[F2]

A null set has dense complement in a positive-dimensional manifold: Let M be a positive-dimensional smooth manifold, let A be a smooth atlas on M, and let E⊆M be A-null (null in the sense of the cited definition). Then M∖E is dense in M. In particular, under Countable Choice the conclusion holds for any manifold-null set E.

[F3]

A Euclidean bump for a compact set inside an open set: If K⊆U⊆Rn with K compact and U open, then there exists a smooth function ρ:Rn→[0,1] such that ρ=1 on K and supp⁡(ρ)⊆U.

[F4]

Compactly supported smooth vector fields are complete: Assume ACω (The Axiom of Countable Choice (ACω)). Every compactly supported smooth vector field on a smooth manifold is complete.

[F5]

Local and global flows generated by a vector field: Let X be a smooth vector field on M. A local flow of X consists of an open set D⊆R×M containing {0}×M and a smooth map Φ:D→M such that: Φ(0,p)=p for every p∈M; for each p, the fibre Dp:={t:(t,p)∈D} is an interval; for each p, the curve t↦Φ(t,p) is an integral curve of X on Dp; and whenever both sides are defined, Φ(t,Φ(s,p))=Φ(t+s,p). If D=R×M, then Φ is the global flow of X.

Proof

Given: The objects and hypotheses in the statement, and a prescribed neighbourhood W0 of A in V.

1.1A1F1F2choose

Choose a product neighbourhood k:A×Rd→U of A with U⊆W0, write π:A×Rd→Rd for the projection, and put B0:=k−1(B∩U)⊆A×Rd. Since B∩U is open in B, the set B0 is an embedded submanifold of dimension dim⁡B; the projection π is smooth, hence C1, and dim⁡B0≤dim⁡B<d, so π(B0) is a null subset of Rd with dense complement, and an arbitrarily small nonzero w lies outside it.

1.2F3F4F5A1construct

Fix r>0, restrict the choice of w to 0<∣w∣<r, and choose a smooth cutoff χ:Rd→[0,1] with χ=1 on the closed ball of radius r about 0 and supp⁡χ in the ball of radius 2r; it exists by [F3] after normalizing any bump for the compact ball inside the larger ball. Define a vector field X on V by X(k(a,z)):=χ(z) (0,w) in the coordinates of U and X:=0 on V∖U. The field is smooth, for the two definitions agree near ∂U where supp⁡χ is avoided, and its support is contained in k(A×supp⁡χ), a compact subset of U; hence it is complete and has a global flow Φ:R×V→V.

2.1F5step 1.2algebra

The time-one map h:=Φ1 is a diffeomorphism of V with inverse Φ−1, it is supported in U⊆W0, and t↦Φt is a smooth isotopy from the identity to h. Because the cutoff is fixed and the field is linear in w, the field tends to zero in every coordinate derivative as w→0. Its flow tends smoothly to the identity: apply The fundamental theorem on flows to the augmented field with w as a constant parameter coordinate, using a parameter cutoff outside a fixed ball. Its support is compact since A is compact, so the flow is defined for the entire time interval. Smooth dependence on (w,t,x) and compactness give convergence of every derivative. For a∈A the trajectory of k(a,0) is t↦k(a,tw), because along the segment from 0 to w the cutoff equals 1 and the second coordinate moves linearly; hence h(k(a,0))=k(a,w), that is, h(A)=k(A×{w})⊆U.

3.1step 1.1step 2.1algebra∎

Finally h(A)∩B=∅: a point of h(A)∩B would lie in U and equal k(a,w) for some a∈A; then (a,w)∈B0, contradicting w∉π(B0), since π(a,w)=w. Together with steps 1.1 and 2.1 this gives a diffeomorphism supported in the prescribed neighbourhood, isotopic to the identity, that moves A off B. If B=∅ or A=∅ the identity map already satisfies the conclusion, and the construction above also covers these cases because then π(B0) is empty.

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