Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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A null set has dense complement in a positive-dimensional manifold

Statement

If M is a positive-dimensional smooth manifold and EM is null, then ME is dense in M.

Facts & Assumptions

Given: A positive-dimensional smooth manifold M and a null subset EM.

[L1]

A countable chart cover detects manifold nullity (A countable chart cover detects manifold null sets).

Proof

technique · direct
1.1

Suppose ME were not dense. Then some nonempty open set OM would satisfy OE. Choose a chart (U,φ) with UO and φ(U)Rm, where m=dimM1.

givenassume-contrachoose
2.1

Since UE, the chart image φ(U) would be a null subset of Rm by [L1]. But φ(U) is a nonempty open subset of Rm, so it contains a closed cube of positive side length and therefore cannot be null. Contradiction.

L1step 1.1contradiction
3.1

Hence every nonempty open subset of M meets ME, so ME is dense.

discharge-contradiction: dense complementstep 2.1

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources