Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
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An equidimensional C1 map sends null sets to null sets

Statement

Let F:MmNm be a C1 map between smooth manifolds of the same dimension. If EM is null, then F(E)N is null.

Facts & Assumptions

Given: A C1 map F:MmNm and a null subset EM.

[L1]

A countable chart cover detects manifold nullity (A countable chart cover detects manifold null sets).

[L2]

On compact coordinate pieces a C1 map is locally Lipschitz, and Lipschitz maps send Euclidean null sets to Euclidean null sets (A C1 map is locally Lipschitz on compact coordinate subsets, A Lipschitz map RmRm sends null sets to null sets).

Proof

technique · direct
1.1

Choose countable smooth atlases on M and N detecting nullity by [L1]. Refine the source atlas so that each relatively compact chart domain lies inside the inverse image of one target chart domain.

L1givenchoose
2.1

For each source chart piece Uj, the set φj(EUj) is null in Rm. Cover Uj by finitely many smaller coordinate neighbourhoods on which the coordinate representative of F is Lipschitz by [L2]. Applying [L2] on each such piece shows that the corresponding target-chart image of F(EUj) is null.

L2step 1.1algebra
3.1

The set F(E) is the countable union of the sets F(EUj). Since each has null image in every target chart from step 2.1, [L1] implies that F(E) is null in N.

L1step 2.1algebra

Depends on

Used by

Dependency tree · two levels

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