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A countable chart cover detects manifold null sets
Statement
Let be a smooth manifold. If is a countable smooth atlas with relatively compact domains, then a subset is null if and only if every is null in when , and every is empty when .
Facts & Assumptions
Given: A countable smooth atlas with relatively compact domains on a smooth manifold .
On a -manifold, the only null subset is the empty set (Null subsets of a smooth manifold).
Nullity is independent of the chosen smooth atlas (The null-set definition is independent of the smooth atlas).
Proof
If , [F1] says that is null exactly when . Because the chart domains cover , this is equivalent to every being empty, hence to every chart image being empty.
Assume . If is null, then every chart image is null by definition.
Conversely, the given countable atlas is itself a smooth atlas, so [L2] says that being null with respect to this atlas is the same as being null with respect to any other. Therefore the displayed chartwise condition implies that is null.
Hence this countable chart cover detects manifold null sets in every dimension.
Depends on
Used by
- A null set has dense complement in a positive-dimensional manifold Proposition
- An equidimensional C¹ map sends null sets to null sets Proposition
- Countable unions and subsets of manifold null sets are null Proposition
- The image of a lower-dimensional C¹ manifold is null Proposition
- Morse-Sard for smooth manifolds Theorem
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John M. Lee, Introduction to Smooth Manifolds, 2nd ed. (standard reference, not scraped)