Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A Lipschitz map RmRm\mathbb{R}^m\to\mathbb{R}^m sends null sets to null sets

Statement

If T:RmRmT:\mathbb R^m\to\mathbb R^m is Lipschitz and EE is null, then T[E]T[E] is null.

Facts & Assumptions

Proof

technique · cases
1.1

If L=0L=0, T[E]T[E] is empty or a singleton, covered by cubes of arbitrarily small side.

assume-case zeroL1given
1.2

Suppose L>0L>0. The image of a side-\ell cube lies in a cube of side CmLC_mL\ell, where CmC_m is the fixed norm-comparison factor. Its volume is (CmL)mm(C_mL)^m\ell^m.

assume-case positiveL1L2given
2.1

Given an output budget ε\varepsilon, cover EE by cubes with total volume below ε/(CmL)m\varepsilon/(C_mL)^m. Replacing each by its image-containing cube gives a cover of T[E]T[E] with total volume below ε\varepsilon.

step 1.2given
3.1

Both cases prove nullity. Equal domain and codomain dimensions are used in the volume scaling.

step 1.1step 2.1cases-exhaustive

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 168 results over 28 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources