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On a small cube, a diffeomorphism distorts Jordan content by factors arbitrarily close to its linearized absolute determinant
Statement
Let , let be on an open set, let , and suppose is invertible. For every there is a closed cube centred at , of positive radius and contained in , such that every Jordan set has Jordan image and The cube may be chosen inside any prescribed neighborhood of .
Facts & Assumptions
Given: The map, the point , invertible , and .
A linear endomorphism maps Jordan sets to Jordan sets and scales content by its absolute determinant (A linear endomorphism of sends bounded Jordan sets to bounded Jordan sets and scales their content by the absolute determinant).
A map whose derivative is uniformly close enough to the identity sandwiches each sufficiently small cube between concentric contracted and expanded cubes (A map uniformly close to the identity derivative sandwiches a cube between contracted and expanded cubes).
Jordan inner and outer content approximate Jordan sets by finite rectangular figures (Jordan inner and outer content and Jordan measurable bounded sets in ).
A derivative bound on a convex open set gives a Lipschitz bound (On a convex open set, a uniform bound implies ); an everywhere-invertible derivative gives local inverses (The Euclidean inverse function theorem); Lipschitz self-maps preserve null sets (A Lipschitz map sends null sets to null sets); and bounded sets are Jordan exactly when their boundaries are null (A bounded set in is Jordan measurable iff its boundary is null, equivalently of content zero).
Jordan content is finitely additive across Jordan pieces whose overlaps have content zero (Jordan content is finitely additive when the overlap has content zero).
Proof
Normalize at by the affine map Choose and a slightly larger cube inside on which . The mean-value bound in [L4] makes a -contraction in the sup norm, so is injective and bi-Lipschitz there. The derivative bound also makes every invertible; the inverse function theorem in [L4] therefore makes a homeomorphism on a neighborhood of the smaller positive-radius cube . Here and ; continuity of permits the stated choice inside any prescribed neighborhood.
If is Jordan, the homeomorphism in step 1.1 gives . Compose on the larger cube with coordinatewise clamping onto that cube to obtain a global Lipschitz map. Since is null, [L4] makes null and hence makes Jordan.
Refine inner and outer figures from [L3] into finite unions of sufficiently small, interior-disjoint cubes with arbitrarily small content gap. After translating at each cube centre, [L2] sandwiches its -image between cubes with factors and . Step 2.1 makes those images Jordan, injectivity makes their interiors disjoint, and [L5] adds their contents. Letting the figure gap vanish gives the stronger bounds with ; since , these imply the displayed bounds for . Finally , so [L1] multiplies every content by .
Depends on
- The Jacobian determinant of a square-dimensional $C^1$ map is the determinant of its Jacobian matrix
- A linear endomorphism of $\mathbb R^n$ sends bounded Jordan sets to bounded Jordan sets and scales their content by the absolute determinant
- A $C^1$ map uniformly close to the identity derivative sandwiches a cube between contracted and expanded cubes
- Jordan inner and outer content and Jordan measurable bounded sets in $\mathbb{R}^m$
- On a convex open set, a uniform bound $\|Df(z)v\|_2\le M\|v\|_2$ implies $\|f(y)-f(x)\|_2\le M\|y-x\|_2$
- The Euclidean inverse function theorem
- A Lipschitz map $\mathbb{R}^m\to\mathbb{R}^m$ sends null sets to null sets
- A bounded set in $\mathbb{R}^m$ is Jordan measurable iff its boundary is null, equivalently of content zero
- Jordan content is finitely additive when the overlap has content zero
Used by
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Sources
- A. Leibman, Multidimensional Real Analysis, Lemma 5.5.6 and Theorem 5.5.7 (standard reference, not scraped)