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Jordan inner and outer content and Jordan measurable bounded sets in
Definition
For bounded , in the metric sense of Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space, its Jordan outer content is the infimum of over finite axis-parallel rectangle covers of . Its Jordan inner content is the supremum of the same sums over finite families of rectangles contained in whose interiors are pairwise disjoint.
Metric boundedness always supplies a nondegenerate bounding rectangle. For nonempty , choose and with . Since for every coordinate ( as the set of functions , and , , are metrics on it, The finite and reverse triangle inequalities for a norm; and for every norm on satisfies and is Lipschitz, hence continuous, for clause 3, Open ball, closed ball and sphere in a metric space), the nondegenerate box contains . The empty set lies in any fixed nondegenerate rectangle.
Thus the outer family is nonempty and the same bounding rectangle bounds the inner sums; the empty family gives inner sum . Refining all listed endpoints into one grid and splitting the nested finite sums shows every inscribed sum is at most every covering sum (Grid partitions of a rectangle in , their cells, refinements and mesh, Laws of finite sums and finite products). Completeness therefore supplies finite real extrema (Complete ordered field (least-upper-bound property), Every nonempty set bounded below has an infimum, Greatest lower bound (infimum), Suprema and infima are unique).
The set is Jordan measurable when the contents agree, and their common value is its Jordan content. The empty set and every degenerate rectangle have content .
Depends on
- Axis-parallel rectangles in $\mathbb{R}^m$ and their volume
- Grid partitions of a rectangle in $\mathbb{R}^m$, their cells, refinements and mesh
- Finite sums and finite products, by recursion
- Laws of finite sums and finite products
- Bounded subset, diameter, distance from a point to a set, and distance between two sets in a metric space
- Open ball, closed ball and sphere in a metric space
- $\mathbb{R}^n$ as the set of functions $n \to \mathbb{R}$, and $d_1$, $d_2$, $d_\infty$ are metrics on it
- The finite and reverse triangle inequalities for a norm; and for $n \ge 1$ every norm $N$ on $\mathbb{R}^n$ satisfies $N(x) \le C\lVert x\rVert_1$ and is Lipschitz, hence continuous, for $d_2$
- Complete ordered field (least-upper-bound property)
- Greatest lower bound (infimum)
- Every nonempty set bounded below has an infimum
- Suprema and infima are unique
Used by
- A closed disc of radius r≥0 has Jordan content π r² Corollary
- A closed three-dimensional ball of radius r≥0 has volume 4π r³/3 Corollary
- Jordan content is finitely additive when the overlap has content zero Corollary
- The volume of a radius-r closed n-ball is π^n/2rⁿ/Γ(n/2+1) Corollary
- ((0,1)∖ S)×(0,1) is bounded and open, but its boundary has positive Jordan outer content Counterexample
- A linear bijection need not preserve Jordan content Counterexample
- ℚ∩[0,1] is Lebesgue null and has Jordan outer content one Counterexample
- The Smith–Volterra–Cantor slab S×[0,1] is compact and not Jordan measurable Counterexample
- Compact Jordan exhaustions of open subsets of ℝⁿ Definition
- The Riemann integral of a bounded function over a bounded Jordan measurable set Definition
- The Cantor slab C×[0,1] has content zero in ℝ² Example
- The right triangle {(x,y)∈[0,1]²:x+y≤1} has Jordan content 1/2 Example
- FALSE: every bounded plane set has Jordan area False statement
- Lebesgue outer measure agrees with Jordan outer content on every bounded subset of ℝⁿ False statement
- A bounded open Jordan set has an increasing exhaustion by compact finite unions of grid rectangles with vanishing content remainder Lemma
- If every finite interval cover of A⊆ℝ has total length at least c, then every rectangle cover of A×[0,d] has total area at least cd Lemma
- On a small cube, a C¹ diffeomorphism distorts Jordan content by factors arbitrarily close to its linearized absolute determinant Lemma
- Conventions and proved scope for the Riemann integral in ℝᵐ and Jordan content Remark
- How the Lebesgue change-of-variables formula relates to the published formula for Jordan content Remark
- The term “rectifiable” for Jordan measurable sets is unrelated to rectifiable curves Remark
- A bounded set in ℝᵐ is Jordan measurable iff its boundary is null, equivalently of content zero Theorem
- A bounded set is Jordan measurable iff its indicator is Riemann integrable, and the integral is its Jordan content Theorem
- A linear endomorphism of ℝⁿ sends bounded Jordan sets to bounded Jordan sets and scales their content by the absolute determinant Theorem
- Every open subset of ℝⁿ admits a compact Jordan exhaustion Theorem
- Jordan inner content, outer content, measurability, and content are translation invariant Theorem
- Lebesgue outer measure is at most Jordan outer content, and a bounded Jordan measurable set is Lebesgue measurable with Lebesgue measure equal to its Jordan content Theorem
Dependency tree · two levels
58 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. Lebl, Basic Analysis, Riemann Integral in Several Variables (standard reference, not scraped)
- J. Lebl, Basic Analysis, The Riemann-Lebesgue Criterion (standard reference, not scraped)
- J. Lebl, Basic Analysis, Jordan Measurable Sets (standard reference, not scraped)