Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-01
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((0,1)∖S)×(0,1) is bounded and open, but its boundary has positive Jordan outer content

Statement refuted

Every bounded open subset of R2 is Jordan measurable.

Counterexample

technique · direct
1.1

The set (0,1)∖S is open, so U is open and bounded.

L1
1.2

Every neighbourhood of a point of S×[0,1] meets U, by nowhere density in the first coordinate and the interval factor, and meets the complement. Hence S×[0,1]⊆∂U.

L1given
2.1

Outer content is monotone under inclusion, so [L2] gives the boundary positive outer content.

step 1.2L2given

Depends on

Used by

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Dependency tree · two levels

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Sources