Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-01
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The Cantor slab C×[0,1] has content zero in R2

Example

For the ordinary Cantor set C, the slab C×[0,1] has content zero in R2, and hence Jordan content 0.

Verification

technique · constructive
1.1

Given ε>0, cover C by finitely many positive-width intervals Ir with ∑rℓr and max⁡rℓr sufficiently small. Degenerate members may be enlarged within the budget.

L1chooseconstruct
1.2

Above Ir, stack squares of side ℓr. By [L2], at most 1/ℓr+2 squares suffice, with total area at most ℓr+2ℓr2.

L2given
2.1

Summing gives at most ∑rℓr+2(max⁡rℓr)∑rℓr<ε. Thus the slab has cube-content zero.

step 1.1step 1.2given
3.1

By Jordan inner and outer content and Jordan measurable bounded sets in Rm, cube-content zero makes the Jordan outer content 0. The nonnegative inner content is at most the outer content, so both are 0; the slab is Jordan measurable with content 0, unlike the fat-Cantor slab The Smith–Volterra–Cantor slab S×[0,1] is compact and not Jordan measurable.

step 2.1givendischarge-construct∎

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Dependency tree · two levels

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