Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Q[0,1] is Lebesgue null and has Jordan outer content one

Statement refuted

A Lebesgue null subset of [0,1] must have Jordan outer content 0.

Facts & Assumptions

Given: The Axiom of Countable Choice and the set E:=Q[0,1].

[L1]
[F1]

Its Jordan outer content is the infimum of r<qvol(Rr) over finite axis-parallel rectangle covers of the set (Jordan inner and outer content and Jordan measurable bounded sets in Rm).

[F2]

The same lower bound on total length holds for a finite cover of an interval by bounded intervals of any of the four bounded forms (If finitely many intervals cover a closed bounded interval [a,b], the sum of their lengths is at least ba).

[F4]

The rationals are countably infinite (Q is countably infinite).

Counterexample

technique · direct
1.1

The witness set E=Q[0,1] is countable, hence Lebesgue null by [L1].

L1F4
1.2

Let finitely many bounded intervals cover E. Their union is closed in [0,1], and because it contains the dense subset E of [0,1], [F3] makes it contain all of [0,1].

F1F3algebra
2.1

Therefore [F2] gives total covering length at least 1.

step 1.2F2
3.1

The single interval [0,1] realises total length 1, so [F1] gives Jordan outer content exactly 1. Thus E is Lebesgue null and still has Jordan outer content one.

step 2.1F1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

57 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources