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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-21
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Jordan inner content, outer content, measurability, and content are translation invariant

Statement

Let n≥1. For every bounded E⊆Rn and every a∈Rn, the translates E+a and E have equal Jordan inner and outer contents. Consequently, E is Jordan measurable if and only if E+a is Jordan measurable, and in that case

cont⁡(E+a)=cont⁡(E).

Here translation is as in Translation of a subset of Rn.

Facts & Assumptions

Given: A natural n≥1, a bounded set E⊆Rn, and a vector a∈Rn.

[L1]

For a bounded set, Jordan outer content is the infimum of the total volumes of finite axis-parallel rectangle covers, and Jordan inner content is the supremum of the total volumes of finite interior-disjoint axis-parallel rectangle families contained in the set (Jordan inner and outer content and Jordan measurable bounded sets in Rm).

[L2]

A rectangle [u,v]⊆Rn has volume ∏j<n(vj−uj) (Axis-parallel rectangles in Rm and their volume).

[L3]

The translate of E by a is E+a={x+a:x∈E}, and translation by a is a bijection with inverse translation by −a (Translation of a subset of Rn).

Proof

technique · direct
1.1L1L2L3

Translation by a sends every axis-parallel rectangle [u,v] bijectively to [u+a,v+a], preserves all side lengths and volumes by [L2], preserves containment and interior-disjointness, and sends finite covers or inner families for E to families of the same total volume for E+a; this also covers the empty family, the empty set, and rectangles with zero side length.

2.1step 1.1L1

Step 1.1 gives outer content of E+a at most that of E and inner content of E+a at least that of E; applying the same argument to translation by −a gives the reverse inequalities, so both respective contents are equal.

3.1step 2.1L1∎

Equality of the two contents for E is therefore equivalent to equality of the two contents for E+a, and when these equalities hold their common values agree.

Depends on

Used by

Dependency tree · two levels

19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources