Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A smooth map from lower to higher dimension cannot be surjective

Statement

If F:MmNn is smooth and m<n, then F is not surjective onto any nonempty N.

Facts & Assumptions

Given: A smooth map F:MmNn with m<n and N.

[L1]

The image of a lower-dimensional C1 manifold is null (The image of a lower-dimensional C1 manifold is null).

[L2]

In a positive-dimensional manifold, a null set has dense complement (A null set has dense complement in a positive-dimensional manifold).

Proof

technique · direct
1.1

By [L1], F(M) is a null subset of N. Since m<n, the target dimension is positive.

L1given
2.1

If F were surjective, then N=F(M) would be null in itself. But [L2] would then force its complement to be dense in N, impossible because N is nonempty.

L2step 1.1contradiction
3.1

Hence F cannot be surjective.

discharge-contradiction: surjectivity impossiblestep 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources