Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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Through each point there is a unique maximal integral curve

Statement

For every point pM and every smooth vector field X on M, there is a unique maximal integral curve γp:IpM of X with γp(0)=p.

Facts & Assumptions

Given: A smooth vector field X on M and a point pM.

[L1]

Through each point there is a unique integral curve on some open interval about 0, depending smoothly on the initial value (Local existence, uniqueness, and smooth dependence for manifold integral curves).

Proof

technique · direct
1.1

By [L1], there exists at least one integral curve of X through p on some open interval about 0. If two such curves are defined on overlapping intervals, [L1] forces them to agree on the overlap because they solve the same initial-value problem at any common time.

L1given
2.1

Let Ip be the union of all intervals carrying an integral curve through p, and define γp(t) by any one of those curves. Step 1.1 shows this is well defined on Ip. Because all the intervals contain 0 and pairwise overlap along the common trajectory, their union is again an interval.

step 1.1construct
3.1

The map γp:IpM is an integral curve, since near each tIp it coincides with one of the local curves from which it was assembled. If it extended to a larger interval, that larger curve would belong to the family defining Ip, contradicting the definition of the union.

step 2.1
4.1

Therefore γp is the unique maximal integral curve of X through p.

step 1.1step 3.1

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources