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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
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Geodesics continue while velocity lifts remain compact

Statement

Assume ACω, and let M be a Riemannian manifold without boundary. Let γ:I=(a,b)M be an affinely parametrized geodesic on a nonempty open interval, where either endpoint may be infinite, and write z(t)=(γ(t),γ(t))TM for its velocity lift.

  1. If b< and there are t0I and a compact subset KTM such that z(t)K whenever t0<t<b, then γ extends as a geodesic to an open interval with right endpoint strictly greater than b.
  2. If a> and there are t0I and a compact subset KTM such that z(t)K whenever a<t<t0, then γ extends as a geodesic to an open interval with left endpoint strictly less than a.

Consequently, the velocity lift of a maximal geodesic leaves every compact subset of TM along each tail approaching a finite endpoint of its maximal interval.

Facts & Assumptions

Given: The data in the statement. The boundaryless convention is Boundaryless convention for geodesic flow and Hopf–Rinow.

[A1]
[F1]

The geodesic spray is a well-defined smooth vector field on TM uses [A1] to supply a smooth geodesic spray S on TM whose integral curves are exactly the velocity lifts of affinely parametrized geodesics.

[F2]

Applied to S, The fundamental theorem on flows supplies an open maximal-flow domain DR×TM and a smooth map Φ:DTM; the time curve sΦ(s,w) is the unique maximal integral curve through every wTM.

[F5]

Every nonempty finite set of real numbers has a positive minimum when all its members are positive (Every nonempty finite set of reals has a maximum and a minimum).

Proof

1.1

By [F1], z is an integral curve of S. By [F2], for every wTM one has (0,w)D. Since D is open, [F3] gives an open set UTM containing w and an ε>0 such that (ε,ε)×UD. Thus the set A:={(ε,U):ε>0, UTM open, (ε,ε)×UD} indexes an ambient-open cover (U(ε,U))(ε,U)A of TM, and hence of K.

A1F1F2F3
2.1

The tail hypothesis makes K nonempty. By [F4], finitely many indices (ε0,U0),,(εn,Un)A cover K. By [F5], δ:=min{ε0,,εn}>0. If wK, then wUi for some i, and s<δεi implies (s,w)D. Therefore (δ,δ)×KD. No pointwise family of choices was made: the index of the cover already contains both U and its admissible ε, and compactness returns a finite list of those pairs.

F4F5step 1.1
3.1

Assume the right-endpoint hypotheses. Put c=max{t0,bδ/2}<b and t1=(c+b)/2. Then t1I, t1>t0, z1:=z(t1)K, and bt1<δ/2. Step 2.1 makes sΦ(s,z1) an integral curve for s<δ. By uniqueness in [F2], it agrees with sz(t1+s) wherever both are defined.

F2F5step 2.1givenalgebra
4.1

Projecting the curve in step 3.1 to M gives a geodesic by [F1]. It agrees with γ on the overlap, so it glues smoothly to γ and defines a geodesic on I(t1δ,t1+δ)=(a,t1+δ). Because t1+δ>b, this is the required extension past b. Notice that the new interval contains the formerly missing parameter value b; no value of γ at b was assumed.

F1F2step 3.1
5.1

For a finite left endpoint, put c=min{t0,a+δ/2}>a and t1=(a+c)/2. Then z(t1)K and t1a<δ/2. The same maximal-flow curve, now using negative times, glues to z and projects to a geodesic on (t1δ,b), whose left endpoint is strictly less than a. This proves claim 2. If γ were maximal, either extension would contradict maximality; contraposition gives the final consequence.

F1F2F5step 2.1step 3.1step 4.1
6.1

The empty manifold admits no geodesic with nonempty domain. In dimension zero the spray curves are stationary, and in dimension one the preceding argument is unchanged; no positive-dimensional coordinate was used. An empty K cannot contain the nonempty tail, while a one-member finite subcover is allowed and gives δ=ε0. Only finite endpoints are asserted, and steps 4.1 and 5.1 treat both endpoint directions. The sole choice principle is the stated ACω used through [F1]; the compact-cover argument itself is a ZF argument and makes no countable or arbitrary selection.

A1F1step 1.1step 2.1step 4.1step 5.1

Remarks

  • Datar's proof of Proposition 20.2.2 gives the same endpoint-extension move for an integral curve once a subsequence converges in a compact set. Andrews, Theorem 11.5.1, printed pp.106--107, instead obtains a limiting base point from metric completeness and continues a radial geodesic there. Neither source states the finite-flow-box proof verbatim; the exact uniform compact argument above is derived from the published maximal-flow theorem [F2].
  • Compactness of the image in M alone would not suffice here: the initial condition for the spray is the full velocity lift in TM.

Depends on

Used by

Dependency tree · two levels

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Sources