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LemmaStatement: AI-generatedProof: AI-generated
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Vacuum curvature of a globally static product

Statement

For the static product of the regular exterior data, the equation Ric⁡(g)=0 on R×X is equivalent to ΔhV=0,D2V=VRic⁡(h). When these equivalent conditions hold, the scalar curvature of h is zero. The displayed spatial equations then extend continuously to B when h,V are C2 there, in the multiplication form displayed above.

Facts & Assumptions

[F1]

The formulation and calculations use the following exact object, operator and earlier-result interfaces: Complete regular static exterior data and its normalized end Stationary Lorentzian data and tensor conventions Gradient hessian and divergence connection formulas

[F2]

On the smooth interior, the Riemannian Christoffel formula applies to the positive-definite metric h, and the nondegenerate four-metric Christoffel formula applies to g=−V2dt2+h because V>0 there. The ZFC convention of [F1] includes the countable choice assumed by the latter supplier. Christoffel formula for the levi civita connection Existence and uniqueness of the metric-selected connection of a nondegenerate metric, and its extension to tensor fields

[F3]

For the smooth Riemannian metric h on X, scalar curvature is the metric trace of its Ricci tensor: Scal⁡(h)=hijRic⁡ij(h). The ZFC convention of [F1] includes the countable choice assumed by this definition. Scalar curvature

[F4]

On the smooth Riemannian interior, Ric⁡(h)(A,C)=tr⁡(Z↦Rh(Z,A)C), with Rh(A,C)E=DADCE−DCDAE−D[A,C]E. This curvature sign agrees with the Lorentzian convention in [F1]. Ricci curvature

Proof

Given: The static product of [F1], its Levi–Civita curvature conventions and coordinate Hessian formula, the Christoffel formulas in [F2], the scalar-curvature definition in [F3], and the Riemannian Ricci definition in [F4].

Goal: Derive the spatial equations, rather than presume a static vacuum reduction.

1.1givenF1F2F4

In product coordinates, gtt=−V2, gti=0 and gij=hij. The Christoffel formulas of [F2] give Γtti=V−1∂iV, Γitt=Vhij∂jV, Γijk=Γijk(h), with all other mixed Christoffel symbols zero. Substituting into Ric⁡ab=∂cΓcab−∂bΓcac+ΓccdΓdab−ΓcbdΓdac yields Ric⁡tt(g)=VΔhV, Ric⁡ti(g)=0, and Ric⁡ij(g)=Ric⁡ij(h)−V−1(∂i∂jV−Γkij(h)∂kV). For the last formula, the extra terms are −∂j(V−1∂iV)+V−1Γkij(h)∂kV−V−2∂iV∂jV=−V−1(D2V)ij.

2.1givenF1F3step 1.1∎

Since V>0 in X, vanishing of these components is precisely the two equations in the Statement. Their spatial trace, using [F3], is VScal⁡(h)=ΔhV=0, giving zero scalar curvature. At B all quantities in the multiplication form D2V=VRic⁡(h) and in ΔhV=0 are continuous under the stated C2 hypotheses, so their zero identities have the continuous boundary limits. This extension does not divide by the vanishing lapse.

Depends on

Used by · 3

Dependency tree · 2 levels

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