Alphabeta Math
DefinitionDefinition: AI-generatedProof: AI-generated
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Unimodular elements and trivial summands

PDF p. 1: Serre splitting and top Chern obstruction

Definition

Let A be a commutative ring with identity and P a finite projective A-module: P is finitely generated, and maps from P lift through surjective module homomorphisms. An element p∈P is unimodular if there is an A-linear functional ϕ:P→A with ϕ(p)=1. A functional ϕ:P→A is unimodular if it is surjective. A pair (p,ϕ) with ϕ(p)=1 is a unimodular pair.

A vector bundle E on a scheme X is a finite locally free OX-module: every point has an open neighbourhood on which E is a finite direct sum of copies of OX. Its dual is E∨=HomOX(E,OX). A global section s∈Γ(X,E) is nowhere zero if, at every point x, its image in the fiber E⊗OXk(x) is nonzero, where k(x) is the residue field of the local ring OX,x. Equivalently, locally on X the map OX→E, 1↦s, identifies OX with a direct summand of E. A morphism E→OX is instead a global section of the dual E∨.

Assume the Axiom of Choice for the following affine correspondence. On X=Spec⁡A, the bundle associated to a finite projective module P has global sections P; under this identification a section is nowhere zero exactly when its element is unimodular. A unimodular pair gives an isomorphism A⊕ker⁡ϕ→P, (a,q)↦ap+q. In particular, a surjective functional on P belongs to such a pair.

Justification

The fiber condition uses the actual residue class of the section and is independent of a choice of local frame. The equivalences and the displayed direct-sum decomposition are established below. The affine assertion uses the stated Axiom of Choice through the cited affine module–bundle interface.

Facts & Assumptions

Given: A commutative ring A, a finite projective A-module P, a scheme X with a vector bundle E, and the Axiom of Choice for the affine assertions.

Goal: Justify the local description of nowhere-zero sections and the stated affine equivalences and splitting.

[F1]

Under the Axiom of Choice, finite projective A-modules and vector bundles on Spec⁡A correspond by associated sheaf and global sections, compatibly with localizations and duals; a finite projective module is a direct summand of a finite free module. Affine bundles and finite projective modules

Proof

technique · direct; use local coordinates and the affine module–bundle correspondence
1.1givenconstruct

On a neighbourhood of a point x, choose a frame of E and write s=(a1,…,ar). Its fiber value at x is nonzero exactly when some ai has nonzero image in the residue field of OX,x, equivalently is a unit in that local ring. After shrinking the neighbourhood, that coordinate is invertible. Projection to this coordinate followed by multiplication by ai−1 is then a functional taking s to 1, so s generates a direct summand. Conversely, if such a local splitting exists, its fiber sends the fiber value of s to 1, so that value is nonzero. Thus the two local descriptions agree.

1.2givenalgebraconstruct

If ϕ(p)=1, the map (a,q)↦ap+q from A⊕ker⁡ϕ to P has inverse v↦(ϕ(v),v−ϕ(v)p). If ϕ is surjective, choose p with ϕ(p)=1. These statements also hold for the zero ring, where 1=0.

1.3F1givenconstruct

For the affine converse, write P as a direct summand of An using [F1]. The resulting coordinate functionals λi∈P∨ and elements ei∈P satisfy v=∑iλi(v)ei for every v∈P. Put I=(λ1(p),…,λn(p)). At a prime p, the fiber of the associated section is zero exactly when all λi(p) lie in p: one direction follows by applying the functionals and the other from the displayed expansion. If the section is nowhere zero, I is contained in no prime. Under Choice a proper ideal lies in a maximal, hence prime, ideal, so I=A. Coefficients expressing 1 as a linear combination of the λi(p) yield a functional ϕ with ϕ(p)=1.

2.1F1step 1.1step 1.2step 1.3∎

Conversely, if ϕ(p)=1, its localization and passage to every residue field send the fiber value of p to 1; hence that value is nonzero. Steps 1.1 through 1.3 and this implication establish all the stated equivalences and the splitting.

Depends on

Used by · 2

Dependency tree · 2 levels

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