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Closed immersions preserve residue fields

PDF p. 5: HK18 Theorem 1.4

Statement

Let i:Z→X be a closed immersion of schemes. For every z∈Z, putting x=i(z), the local stalk homomorphism OX,x→OZ,z is surjective and its induced residue-field homomorphism κ(x)→κ(z) is an isomorphism. The residue field of a local ring is its quotient by its unique maximal ideal. No additional finiteness, noetherian or reducedness hypothesis is required.

Facts & Assumptions

Given: A closed immersion i:Z→X and a point z∈Z, with x=i(z).

[F1]

A closed immersion is a homeomorphism onto a closed subset and has a surjective structure-sheaf morphism OX→i∗OZ. Closed immersions of schemes

[F2]

A morphism of schemes is a morphism of the underlying locally ringed spaces; its stalk homomorphisms are local. Morphisms of schemes

[F3]

Stalk elements are germs of sections over open neighbourhoods, with equality tested after restriction to a smaller neighbourhood. The direct image has sections (i∗OZ)(U)=OZ(i−1U) and the inherited restriction maps. The stalk of a presheaf at a point Direct image of a sheaf along a continuous map

[F4]

A sequence of sheaves of abelian groups is exact if and only if its stalk sequences are exact. In particular a surjective structure-sheaf morphism is surjective on stalks, by applying this criterion to its underlying additive sheaves. A sequence of abelian sheaves is exact exactly when it is exact on every stalk

[F5]

The residue field of a local ring is its quotient by its unique maximal ideal. A local stalk map of a morphism of locally ringed spaces induces a unital field homomorphism on these quotients. A local ring is a nonzero commutative ring with a unique maximal ideal A local morphism of stalks induces a residue-field map

Proof

Goal: Prove surjectivity on local rings and the induced residue-field isomorphism.

Proof technique: Identify the direct-image stalk by germs and then pass to residue fields.

1.1F1F3F4given

By [F1], every open neighbourhood W of z in Z is i−1U for an open neighbourhood U of x in X: the image i(W) is open in the subspace i(Z), so it is i(Z)∩U for some open U⊆X, which necessarily contains x. Thus [F3] identifies (i∗OZ)x with OZ,z. Indeed every section germ at z is represented on such an i−1U, and equality of two germs is detected on another such neighbourhood, so the identification is both surjective and injective and respects ring operations. By [F4], the surjective sheaf morphism of [F1] induces a surjection OX,x→(i∗OZ)x. Under the germ identification this is the stalk homomorphism of i, proving its surjectivity.

2.1F2F5step 1.1∎

By [F2] and [F5], this stalk homomorphism induces a unital field homomorphism κ(x)→κ(z). It is surjective: represent an element of κ(z) by an element of OZ,z, lift it using step 1.1 and take the residue class of that lift. It is injective: if a nonzero source element mapped to zero, its inverse would force 1=0 in the target field, a contradiction. Hence the induced homomorphism is an isomorphism. If Z is empty, the pointwise assertions are vacuous.

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