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Cofiber bounds imply low-degree cohomology isomorphisms
PDF p. 4: equivalence in degrees at most three
Statement
Let be a morphism in and let be its cofiber, represented by a mapping cone. If for every , then is an isomorphism for every and is injective for . If, in addition, , it is an isomorphism also for .
Facts & Assumptions
Given: A derived-category morphism and a cone with the stated vanishing.
Goal: Establish the stated low-degree consequences.
Cohomology is a functor on (Cohomology descends to the derived category).
Proof
Represent the derived morphism by a chain map after replacing its source by a quasi-isomorphic complex. Its mapping cone fits in a degreewise split short exact sequence of complexes . Taking cycles and boundaries gives the long exact sequence . The result is independent of representatives by [F1].
For , both adjacent cone groups in step 1.1 vanish, giving an isomorphism. For , the left group vanishes, giving injectivity; if also , the right group vanishes and the map is surjective as well. This proves every claimed range without a condition on .
Depends on
Used by · 1
Dependency tree · 3 levels
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