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The actual smooth open pair and its choice scope
PDF p. 13: Proposition 6.1 support argument
Statement
Assume AC. Let be an affine finite-type threefold over algebraically closed , let , and let be closed with . Put and . All four schemes are qcqs and are smooth separated finite type over the perfect field . They are regular Noetherian as schemes over the prime field. The two opens cover and their intersection is , giving a Nisnevich two-open covering square. If is an integral curve, it is affine; it lies in one of the open-and-closed relative-dimension strata of .
Facts & Assumptions
Given: The hypotheses in the statement, with the Axiom of Choice and fixed universe bounds.
Goal: Construct the stated actual maps and prove their consequence.
Article scheme conventions, Motivic and filtered K theory with support and Nisnevich covers and distinguished squares fix the finite-type, size, AC and two-open conventions. Basic smoothness here includes its regularity over a perfect field and locally constant relative dimension.
Proof
Finite-type affine is Noetherian and separated. Every open is quasi-compact in a Noetherian space, and its induced scheme is separated finite type. Thus the four objects lie in the completed qcqs category. The smooth locus and its open are smooth over , hence regular Noetherian. An algebraically closed field is perfect: in positive characteristic each polynomial has a root, so Frobenius is surjective; characteristic zero is perfect. Forgetting the map to does not change regularity or Noetherianness.
The inclusion gives and . Open immersions are étale, and each point has a residue-preserving lift to one of these opens, so the family is Nisnevich. A closed subscheme of affine is affine, giving the curve assertion. For a smooth morphism to a field the relative dimension is locally constant; the finitely many dimension strata of are open and closed. The connected integral curve lies in one such stratum. These are component/dimension bookkeeping facts, with no new comparison theorem assumed.
Depends on
Dependency tree · 3 levels
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